Understanding Solid Angle & Calculating Half-Angle in a Cone

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Solid angle is a three-dimensional measure expressed in steradians, representing the area projected on a sphere divided by the square of the radius. To calculate the solid angle of a cone with half-angle 'alpha', one can derive it from the geometry of the cone, where the total angle at the apex is 2alpha. The formula for solid angle is SA = A/r^2, where A is the area on the sphere's surface. For an isotropic source, the solid angle is 4π steradians, while a hemisphere corresponds to 2π steradians. Understanding these concepts is crucial for applications in vector calculus and physics.
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Hi, could someone explain to me the concept and calculation of Solid Angle? I don't think we've actually covered it in our Vector Calculus lectures and I have a question to do on it! Tried searching on the web, but not much information and I really don't understand it.

Also, my question is:
"Calculate the Solid Angle of a cone of half-angle 'alpha'".
What is the half-angle in a cone?
 
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A transversal section through a cone,if done as to contain the axis reveals a triangle.My gues is that in your case,the triangle is isosceles...The 2 rightangle triangle (congruent) each has an angle \alpha...So the total angle is 2\alpha...Use the definition of the solid angle and compute it.

Daniel.
 
A 2D angle in radians is given by s/r (Where s is the arc length subtended by the angle).

Solid Angles are the 3D equivalent and have (dimensionless) units of steraidians. The Solid Angle is the area projected by the solid angle on a sphere of radius r, divided by r squared.

SA=A/r^2

The Solid Angle of an isotropic source, for example would therefore be

4\pi r^2/r^2 = 4\pi

and a hemisphere would be

2\pi

and so on...

Claude.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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