Understanding Solitary Waves: Investigating the Motive Behind Their Formation

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The discussion focuses on understanding solitary waves, specifically solitons, through mathematical analysis of their properties at two different time snapshots. The participants explore the relationship between the heights of the wave at these times, denoted as fa and fb, and how their difference may represent a derivative. There is confusion regarding the terminology used, particularly the concept of a "motive curve," which is suggested to relate to the shape of the wave at different times. The conversation highlights the mathematical process of deriving one curve from another and how this can be used to reconstruct the wave's shape. Overall, the thread emphasizes the mathematical exploration of solitons and their characteristics over time.
somasimple
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Hi,

I'm not really sure the thread fits this forum but I'm not a mathemacian, too. o:)

I posted below a picture of a soliton (solitary wave) and I have some questions about it.
We are seeing two snapshots taken at time t1 and t2.
If t2=t1+a with a, small enough?

Can we say that fb-fa equals a kind like of derivative of f (i.e. f')?
can we say that this difference is the motive/reason of the soliton since fa + (fb-fa) = fb?
 

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If I understand your picture correctly, fa is the height of the wave at a given time, t1, and position,x1, and fb is the height of the wave at a later time, t2, and positon,x2, such that x1-ct1= x2- ct2; in other words, "moving with the wave". Given that, fb-fa= 0. I have no idea what you might mean by "motive/reason" of a soliton.
 
Hi,

The graph/picture shows two aspects of the same soliton at t1 and t2.
fa is the "curve" at t1 and fb is the curve at t2.

I tried with discrete values (the y values of the curves fa and fb) and I found that substracting fb-fa gives a motive (another curve) that looks like the derivative of fa or fb.
If I add this motive curve values to fa then I obtain fb?
(It seems to work).
 
If fa and fb are curves, then what do you mean by "fb-fa"? I don't know how to subtract curves! Do you mean that fb is a function of x, fb(x)= f(x,b) where f(x,t) is the height of the curve at t= b? In that case, fb- fa= f(x,b)- f(x,a) and then
lim_{a\rightarrow b}\frac{fb-fa}{b-a}
is the partial derivative of f with respect to t.

I still don't know what a "motive curve" is! I suspect you are translating from some language I don't speak.
 
Hi,

Sorry for my poor maths language and unfortunately I'm French that complicates our affair.

We could say that fa and fb are the same shape (motive/reason) of the traveling wave taken at diffrent time t1 and t2.
The shape has of course an equation that I do not know but I have discrete values. With these values I can substract 2 digitized curves that gives a third set of values that looks like the derivative of the equation of the shape?

This third set has also an equation but if I consider only the set I have, I can reproduce fb (shape) simply adding the values of fa with the values I got with my previous computation.

Hope it is a bit clearer?
 

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