1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

I Motivation for Lagrangian mechanics

  1. Apr 22, 2016 #1
    I know how to implement Lagrangian mechanics at a mathematical level and also know that it follows the approach of calculus of variations (i.e. optimisation of functionals, finding their stationary values etc.), however, I'm unsure whether I've grasped the physical intuition behind the formulation correctly. In the following, I have written down how I "see" it and hope that people will be able to give me feedback on whether I have understood it correctly at all, or not.

    Instead of determining all the forces that are acting on a particular system and then solving Newton's 2nd law to determine the physical path of the system, we instead take a different approach by considering the possible paths that a system could take between two different configurations and employ variational techniques to determine the actual physical path the system takes between these two points.
    This is advantageous over the Newtonian approach since we don't have to worry about all the different forces acting on the system and avoid the awkwardness of changing between Euclidean coordinates and other curvilinear coordinate systems encountered in solving the equations of motion in Newtonian mechanics, since such a variational approach is coordinate independent and so we can judiciously choose a set of "generalised" coordinates, ##\lbrace q^{i}\rbrace## that enable one to solve the problem as efficiently as possible.

    To use such an approach we first need a function that characterises the dynamics of a physical system for every possible configuration that it could assume. Empirically, we know that the physical state of a system, at a given instant in time, is fully specified through knowledge of the positions, ##\lbrace q^{i}\rbrace## and velocities, ##\lbrace \dot{q}^{i}\rbrace## of all the constituent components of the system at that instant. Thus, such a function, which we call the Lagrangian of the system, must depend on the state of the system at each point in its so-called configuration space. A priori, before considering any particular path of the system through configuration space, the positions and velocities defining the state of the system at a given instant can be chosen independently. This implies that the Lagrangian should be a function of both position and velocity, i.e. ##\mathcal{L}=\mathcal{L}(q_{i},\dot{q}_{i})##.

    Given this, we now wish to distinguish each path that the system can take through configuration space. We do so by assigning a number to each path. This is achieved by defining a functional, ##S##, the action, which maps each given path, ##q(t)=(q_{1}(t),\ldots ,q_{n}(t))## that the system can take, to a real number. Since the Lagrangian evaluated along a given path characterises the dynamics of the system at each instant in time as the system moves along the path, we define the action in terms of this, i.e. $$S\left[q(t)\right]=\int_{t_{i}}^{t_{f}}\mathcal{L}(q(t),\dot{q}(t))dt$$ where ##t_{i}## and ##t_{f}## are the initial and final instants in time, enabling us to quantify the end points of the section of the path we are considering. Note also that we have now evaluated the Lagrangian along a particular path such that ##\mathcal{L}(q(t),\dot{q}(t))##, and ##q## and ##\dot{q}## are no longer independent, but related by ##\dot{q}(t)=\frac{d}{dt}q(t)##.

    With this initial formalism in place, to find the true physical path of the system between two configurations (at two instants in time ##t_{i}## and ##t_{f}##) we invoke a variational principle. This is the so-called principle of stationary action, motivated by empirical observations, it states that the physical path taken by a given system (through configuration space) is the one that extremises the action, ##S## of the system. Thus, we take a putative curve ##\bar{q}(t)## with fixed end points at ##\bar{q}(t_{i})## and ##\bar{q}(t_{f})##, and make variations of the path in the neighbourhood of this curve between these two end points. This induces a variation in the action, and we require that this variation vanishes at first-order. We thus find that for ##\bar{q}(t)## to be the physical path taken by the system (i.e. an extremal path of ##S##), it must satisfy the Euler-Lagrange equation $$\frac{\partial\mathcal{L}}{\partial q}-\frac{d}{dt}\left(\frac{\partial\mathcal{L}}{\partial \dot{q}}\right)=0$$ which is the equation of motion for the system.

    Sorry this is long-winded, but I really want to check that I understand the concept correctly (at least at an intuitive level), so I have put down my thoughts on the subject.
     
  2. jcsd
  3. Apr 22, 2016 #2
    I think you have understood it correctly and expressed it properly. I would just like to say that this force but it is not so approach avoids the concept of force. But the fact is otherwise. You cannot write the potential function in terms of coordinates unless you know the nature of interaction or the nature of force.
     
  4. Apr 22, 2016 #3
    Thanks for taking a look.
    You're right, I didn't word that part particularly well. What I meant was that you don't need to explicitly right out the forces using the Lagrangian formalism; the dynamics can be deduced through knowledge of the how the force affects the potential and also the kinetic energy of the system.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted



Similar Discussions: Motivation for Lagrangian mechanics
  1. Lagrangian mechanics (Replies: 8)

  2. Lagrangian Mechanics (Replies: 1)

  3. Lagrangian mechanics (Replies: 9)

  4. Lagrangian Mechanics (Replies: 2)

  5. Lagrangian mechanics? (Replies: 2)

Loading...