Understanding Spectral Line Width and Causes | Optical Wavelengths

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SUMMARY

This discussion focuses on the causes of spectral line width in optical wavelengths, emphasizing that thermal broadening, including Doppler and collisional broadening, significantly contributes to this phenomenon. The natural line width, a result of the finite lifetime of atomic states, is also discussed, highlighting its mathematical relationship to the uncertainty principle. Additionally, the distinction between emission and absorption spectral lines is clarified, noting that emitted photons are isotropic, leading to dark lines in absorption spectra due to the limited detection of re-emitted light.

PREREQUISITES
  • Understanding of Heisenberg's uncertainty principle
  • Familiarity with thermal broadening concepts, including Doppler and collisional broadening
  • Knowledge of emission and absorption spectra
  • Basic principles of quantum mechanics and atomic states
NEXT STEPS
  • Research the mathematical implications of the uncertainty principle in quantum mechanics
  • Explore the effects of temperature on spectral line broadening in gases
  • Study the principles of isotropic emission and its impact on spectral analysis
  • Investigate the various types of line broadening, including Stark and pressure broadening
USEFUL FOR

Physicists, optical engineers, and anyone studying atomic spectroscopy or interested in the behavior of light in gases will benefit from this discussion.

nickek
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Hi!
I have two questions regarding spectral lines, in the optical wavelengths.

Every line has a width. One reason is the uncertinity in energy of the atomic states according to Heisenberg uncertinity relation. But this is just a very small part of the width, I think. Are there other causes to this, anything involving for example termo movements of the atoms?

The other questions is about emission and absorption spectral lines. If, for example, heating a gas, the gas emitting photons of a wave length corresponding to the switch of energy states in the atoms. A typical time interval is about 10-8 sec for an atom being in excited state; after that time it fall back and emitting a photon, right? But when sending light into that gas, it absorbes the corresponding wavelengths, and it appears dark lines in the spectrum. The explation use to be that the atom absorbes the energy, but shouldn't it fall back and emit a photon of that wavelength after 10-8 sec?

Thank you for your input!
Nick
 
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Yes to temperature widening the spectral lines! Especially temperature I believe!
Dark line because emission can happen in any direction other than towards your eyes!
 
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I believe this is the wrong way to look at it. The fact that lines have a certain width in frequency is a consequence of the fact that they have a finite lifetime. The fact that the width is inversely proportional to the lifetime is mathematical result and is true for every system (i.e. not only in physics) and is sometimes known as the mathematical uncertainty principle: it is if you want a direct consequence of the "definition" of frequency (in Fourier analysis).
 
The reason for the instability of all (atomic) states except the ground state is the coupling to the electromagnetic quantum field, leading to spontaneous emission of a photon and transition from an excited state to a lower-lying state. This is what's known as "natural line width". Spontaneous emission is one of the true quantum features of the electromagnetic field and was discovered by Dirac in 1928.
 
nickek said:
Every line has a width. One reason is the uncertinity in energy of the atomic states according to Heisenberg uncertinity relation. But this is just a very small part of the width, I think. Are there other causes to this, anything involving for example termo movements of the atoms?
There are two sources of thermal broadening: Doppler broadening and collisional broadening. In normal conditions, thermal broadening will be much greater than that due to the natural linewidth.

nickek said:
The other questions is about emission and absorption spectral lines. If, for example, heating a gas, the gas emitting photons of a wave length corresponding to the switch of energy states in the atoms. A typical time interval is about 10-8 sec for an atom being in excited state; after that time it fall back and emitting a photon, right? But when sending light into that gas, it absorbes the corresponding wavelengths, and it appears dark lines in the spectrum. The explation use to be that the atom absorbes the energy, but shouldn't it fall back and emit a photon of that wavelength after 10-8 sec?
You usually are measuring the absorption along the path of the incident light, but the emission will be isotropic, so only a negligible fraction of the light re-emitted by the atoms will be detected.
 
Some other sources of line broadening are Doppler broadening, instrumental broadening, pressure broadening, and Stark broadening.
Doppler broadening can be from random thermal motion, in which case it has Gaussian shape, or could be from looking at a beam, and then it depends on the aperture of the beam and the view. Instrument broadening is due to the limitations of your equipment. Pressure broadening has to do with collisions modifying the lifetime of the excited states. Stark broadening is actually Stark splitting, but if the resolution of your equipment isn't good enough, the split lines blend together and look like broadening.

Ooops, DrClaude already said some of that.
 
Time reversal invariant Hamiltonians must satisfy ##[H,\Theta]=0## where ##\Theta## is time reversal operator. However, in some texts (for example see Many-body Quantum Theory in Condensed Matter Physics an introduction, HENRIK BRUUS and KARSTEN FLENSBERG, Corrected version: 14 January 2016, section 7.1.4) the time reversal invariant condition is introduced as ##H=H^*##. How these two conditions are identical?

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