Understanding Summation Notation

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SUMMARY

The discussion centers on understanding the summation notation for the function V = ∑λ hhh, where the indices i, j, and k each range from 1 to 3. Participants confirm that there are 27 distinct terms in the sum, resulting from the permutations of the indices. A systematic approach is suggested for calculating the terms, akin to the operation of an odometer, which simplifies the process of generating combinations.

PREREQUISITES
  • Understanding of summation notation and its applications
  • Familiarity with permutations and combinations
  • Basic knowledge of mathematical functions and indices
  • Ability to manipulate algebraic expressions involving multiple variables
NEXT STEPS
  • Study combinatorial mathematics to deepen understanding of permutations
  • Learn about advanced summation techniques and their applications
  • Explore mathematical functions involving multiple variables
  • Practice generating combinations systematically using programming tools like Python
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Students, mathematicians, and anyone involved in mathematical modeling or computational mathematics who seeks to enhance their understanding of summation notation and combinatorial processes.

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I know this should be easy and the answer will be glaringly obvious in hindsight but my brain is fried and I can't for the life of me figure this out. My problem is this I have a function as follows;

V = [tex]\sum\lambda[/tex]i,j,k hihjhk (summation over i,j,k where i,j,k = 1,2,3)

I can't work out if this is

V = [tex]\lambda[/tex]1,1,1h13 + [tex]\lambda[/tex]1,1,2h12h2 + ... + [tex]\lambda[/tex]2,3,1h2h3h1 +...

with every permutation of 1, 2 and 3, this should be simple as it is taken as a given in my problem but it is driving me insane.
 
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Yes, what you have so far is correct. And, since there are 3 indices and each can take on 3 values, there will be [itex]3^3= 27[/itex] terms in the sum.
It would help to have a "process" for working through them- I recommend changing the last index through 1, 2, 3, then the next, etc.- just like an odometer turns over in a car.

i,j,k= 1,1,1; 1,1,2; 1,1,3; 1,2,1;1,2,2; 1,2,3; 1,3,1; 1,3,2; 1,3,3;
will be the first 9 terms.
The next 9 will be exactly the same but with first number 2 and the last 9 with first number 3.
 
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Thank you, you may just have rescued my mental health
 

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