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Understanding symmetry and super symmetry

  1. Sep 3, 2013 #1
    Hello,

    I am quiet new to this subject. I am just repeating in a few words, what I have learned so far: The 4 fundamental forces of nature, strong, weak, electromagnetism and gravity. Physicists are trying to re-generate a condition, a very high temperature during the Big Bang, to find out which force actually works during that time. The Weinberg-Glashow and Abdus Salam model unified weak and electromagnetism to electro-weak force. Gravity still lays undefined in the Standard Model. At Planck's scale, physicists observe that the 4 forces of nature unit to One, single force. We have not yet been able to define that force as yet but the quest is on.


    Now the U(1), SU(2), SU(3)........What are these? Can anyone please help me understand, sequentially how the theories evolved? The Grand Unified theory is one which is SU(5)? Does SU stand for special unitary group?

    Kindly help.
     
  2. jcsd
  3. Sep 3, 2013 #2

    mfb

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    There is no way to observe this (yet?). It is just a hypothesis.

    The special unitary groups that correspond to the gauge symmetries of those interactions.

    That is unknown, SU(5) is one of multiple options.
     
  4. Sep 3, 2013 #3

    marcus

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    Hello Shounakbhatta,
    MFB gave you a complete answer, but in addition if you are a novice you might want to know what "unitary" and "special" mean.

    You should learn what a matrix is. Already know? If not it's easy. Know the complex number plane?

    Know how to take the complex CONJUGATE of a complex number
    x + iy goes to x - iy
    it is flipping the complex number plane over the horizontal axis, the x-axis

    Know about the TRANSPOSE of a matrix? Flipping the matrix over its main diagonal, the diagonal from upper left to lower right.

    Know about the INVERSE of a matrix?

    You could keep on questioning. You could ask for people to explain to you what a unitary matrix is.

    How,when you apply a unitary matrix to a vector it does not change the "length" of the vector (by length I mean a generalization of the length idea to vectors of complex numbers---sometimes called the "norm" of the vector. It is kind of a general idea of size (not just of one number but of a string of number, like 3 or 4 numbers). A unitary matrix, working as a transformation of vectors, does not change their size.

    Special basically means it does not change volumes either! Several vectors taken together can define a box-like volume. You need to ask more questions if you aren't familiar with this. I'm speaking a sloppy way. Special unitary matrices, working as transformations, are very nice, the keep sizes and volumes (properly interpreted) the same. It is as if they simply ROTATED the world by some angle and kept it looking basically the same. Not enlarged or shrunk or skewed or stretched in some direction. Nicely behaved.

    SU(2) and SU(3) are groups of 2x2 and 3x3 matrices, especially nicely behaved ones.
     
  5. Sep 4, 2013 #4
    Hello Mfb,

    Thank you very much for the replies.

    Thank you Marcus.

    My question to Marcus: Yes, I have gone through linear algebra and unitary matrix. My questions:

    (a) If we consider SU(5) as the highest level of special unitary, which is a superset of SU(3) and SU(2) and U(1), which is shown as SU(3)xSU(2)xU(1) does it imply that SU(2) is the electroweak unification force and SU(3) and SU(3) is something else and U(1) as the unitary group and ALL of them is unified into SU(5), which is the grand unified theory?

    Secondly, the matrices, what do they represent? Forces? Like strong weak?

    From what you have replied above, the unitary matrices, once rotated, turned, flipped, does not change their size, just like a tensor? It maintains the vectors?

    is that the reason, the fundamental forces of nature are put into unitary matrix to maintain their symmetry? Am I getting close or a dead end?
     
  6. Sep 4, 2013 #5

    marcus

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    Good. Then the person you should be asking your questions of is Mfb.

    BTW you know that for a unitary matrix U, the matrix inverse U-1 is equal to the conjugate transpose, that is often written with a dagger. You might want to learn LaTex for typing math notation. But if you want to write U-dagger without bothering with LaTex you can (at least if your keyboard is like mine) hold down the option key and type a t.

    option-t gives †
    So if you use that as a superscript on a matrix U, you get U
    Then the equation defining unitary matrices is just U-1 = U

    I was simply worried that you might not have taken a course in linear algebra and might not have gone through the definitions of the special unitary matrices. But you have!

    It turns out that I needn't have worried! Apologies for the interruption.
     
  7. Sep 9, 2013 #6
    Hello Marcus,

    I have got your point, but my question still remains unanswered. If the GUT, SU(5) is a super set of SU(3) x SU(2) x U(1), then how the fundamental forces are related to special unitary group?
     
  8. Sep 20, 2013 #7
    Gauge Theory 101.

    Elementary particles' symmetries can be expressed as matrices operating on their multiplets:

    ψ -> R.ψ

    where ψ is the field and R the matrix. For groups like U(n) and SU(n), R is unitary. An easy case is electric charge, which is U(1):
    R = exp(i*q*a)

    where q is the charge and a is an overall variable for the different particles. For electric charge, it's easy to see that
    Product of incoming particles' R's = product of outgoing particles' R's
    One gets it from
    Sum of incoming particles' q's = sum of outgoing particles' q's

    Larger groups have several a's in their R's.

    If a is independent of space-time, then the symmetry is global. But if it depends on space-time, then the symmetry is local. But one gets some complications with the fields' kinetic terms. They contain differential operators: D(ψ)

    D(R.ψ) = D(R).ψ + R.D(ψ)

    The D(R) terms are what cause the trouble, since they disrupt the symmetry of the fields. But if one adds a "gauge field" A, then it can absorb the D(R) terms.

    Let the "gauge covariant" derivative be DA(ψ) = D(ψ) - i*g*A.ψ

    Let A transform as (R.A - (i/g)*D(R)).R-1

    Then DA(R.ψ) = R.DA(ψ)

    The gauge field has absorbed the awkward local-symmetry term, and the symmetry is restored.

    In the electromagnetic case, we get
    A -> A + (q/g)*D(a)
    the familiar gauge symmetry the electromagnetic potentials.


    One can construct a better-behaved quantity from the A's:
    DAi(DAj(ψ)) - DAj(DAi(ψ)) = - i*g*Fij

    One gets
    F -> R.F.R-1
    under this symmetry, without weird derivative terms.

    For electromagnetism, F is the familiar electromagnetic-field tensor, a tensor which contains the electric and magnetic fields.


    I've fuzzed over a lot of details here, but I hope that I've made the overall ideas reasonably clear.
     
  9. Sep 20, 2013 #8
    I'll continue.

    Continuous groups can be constructed from generators, and these generators from elements of those groups that are close to the identity element:

    R = 1 + i*ε*L + O(ε2)

    for small ε and generator L. A group may have several generators, and their effects can interact with each other. The generators form a "Lie algebra", and there's a well-developed theory of Lie algebras, like which ones there can possibly be. It's often much easier to use a continuous group's generator algebra to find various results about that group than the group's elements themselves.

    For a unitary group U(n), there are n2 generators, and for SU(n), n2 - 1 generators. The group of orthogonal matrices SO(n) has (1/2)n(n-1) generators, and the spinor group Spin(n) shares its generator algebra. There's also a group of "symplectic" matrices, Sp(2n), with n(2n+1) generators. The algebras for SU(n), SO(n), and Sp(2n) are all "simple" Lie algebras, and there are five additional ones, the exceptional ones G2, F4, E6, E7, and E8.


    Back to gauge theories.

    In a gauge theory, each gauge-field mode corresponds to a generator of the theory's symmetry group. If some generators interact with each other, then the corresponding gauge-field modes also interact with each other.

    For electromagnetism, it's easy. The photon corresponds to the electric charge, with symmetry U(1).

    For quantum chromodynamics, it's much more complicated. A quark has three states, red, green, and blue, and an antiquark has three states, antired or cyan, antigreen or magenta, and antiblue or yellow. The gluon has color-anticolor states, and at first sight, one expects 9 states. But one can form a colorless state from those, so the gluon only has 8 states. Working it out mathematically, QCD has color symmetry group SU(3), 8 generators and all.

    For electroweak unification, one gets two symmetry groups with their associated particles, "weak isospin" with group SU(2), sort of like QCD with only 2 "colors", and "weak hypercharge", with group U(1), just like electric charge.

    Electroweak symmetry is broken, of course, and the surviving symmetry is the U(1) of electric charge.
     
  10. Sep 20, 2013 #9
    So for the Standard Model, we have symmetry group SU(3)*SU(2)*U(1)

    SU(3) = QCD = colors red, green, blue
    SU(2) = weak isospin = "colors" up, down, like the spin states of a spin-1/2 particle
    U(1) = weak hypercharge -- like electric charge

    In fact, (electric charge) = (projected weak isospin) + (weak hypercharge)

    There's been a lot of effort expended on Grand Unified Theories, and I'll briefly mention some of them.

    A simple one is the Georgi-Glashow SU(5) theory. It has 5 "colors":
    QCD red, green, blue; weak-isospin up, down

    One gets weak hypercharge from a generator that responds 1/3 to the QCD "colors" and -1/2 to the WIS "colors".

    Thus, 12 of the 24 SU(5) generators become the QCD, WIS, and WHC generators; 8, 3, and 1 each. This leaves 12 additional ones, and they correspond to gauge particles that make isolated protons decay.

    Proton decay has been searched for, and a recent lower limit to the proton's mean life is around 1030 years or so. This corresponds to a SU(5) symmetry-breaking energy of about 1016 GeV. That's about how massive the proton-decayer particles have to be.


    But the SU(5) theory has the plus of putting each generation of elementary fermions into two multiplets, three if one counts right-handed neutrinos.

    Some GUT's go even farther, like SO(10). They put each generation of elementary fermions into 1 multiplet.


    How much further can one go? According to string theory, one can fit *all* of the Standard Model's particles into *one* multiplet of a big symmetry group called E8. The smallest one, with size 248. It would include all the generations of elementary fermions, as well as the gauge and Higgs particles.
     
  11. Sep 20, 2013 #10
    Thanks Ipetrich.

    Perhaps would like to field a few questions I've been having.

    1) Is it true that each generator corresponds to a separate particle field? Is there a coupling constant even in the interaction of fields of the same symmetry group?

    2) Is it only the Higgs mechanism that breaks the SM symmtries? Or are there other ways of breaking the symmtries?

    Thanks.
     
  12. Sep 20, 2013 #11
    Separate particle field, yes, though a member of a gauge-particle multiplet.

    When self-interacting, the fields share the coupling constant that they have when interacting with other fields.

    The gluon is a color-state multiplet with states sort of like this:
    red-yellow
    red-magenta
    green-yellow
    green-cyan
    blue-magenta
    blue-cyan
    (red-cyan - green-magenta)/sqrt(2)
    (red-cyan + green-magenta - 2*blue-yellow)/sqrt(6)

    The ninth possible state is colorless:
    (red-cyan + green-magenta + blue-yellow)/sqrt(3)

    The Standard Model's electroweak symmetry is indeed broken by the Higgs particle.

    There are other ways of breaking symmetries, but I'd have to research them.
     
  13. Sep 20, 2013 #12
    Before I get into supersymmetry, I'll mention space-time symmetries.

    One handles them in roughly the same way as one handles gauge symmetries. Their generators have some connections with some conserved quantities:

    Space translations - Momentum
    Time translation - Energy
    Rotations - Angular Momentum
    Boosts - Centroid Position

    Something like EM gauge symmetry - electric charge

    In general, continuous symmetries and conserved quantities are connected, and that connection is Noether's theorem.


    Now for supersymmetry.

    It's a symmetry that relates particles with different spins. More precisely, spins differing by 1/2. A SUSY generator applied to a particle field turns it into one with spin differing by 1/2. SUSY generators turn bosons into fermions and fermions into bosons. They are related to space-time ones, as one would expect from their changing of spin, though not to gauge ones.

    So all members of a SUSY multiplet would have the same gauge interactions, like the same electric charges. This is true of their interactions in general, and also of their masses.

    But we don't observe SUSY partners of known particles at those particles' masses, so SUSY must be broken at energies of at least about a TeV.

    But it's nevertheless interesting, because it could help explain why the Standard Model has particles with spins 0 and 1/2, particles with no clear connection to some symmetry.
     
  14. Sep 20, 2013 #13
    I have a hard time assimilating this statement. I assume there is a set of coupling constants between the fields of one group, say SU(3), that multiply each other when fields of only that symmetry group interact with each other. Then there is another set of coupling constants associated with the fields of another group, say SU(2), that are used when only the SU(2) fields interact with each other. But when fields of SU(2) interact with fields of SU(3), what coupling constants are used then, a multiple of coupling constants used when the fields interacted only with there own kind?

    When you say the Higgs mechanism breaks the symmetry of the electroweak symmetry, does that mean it breaks it into the weak symmetry, SU(2), and the electromagnetic symmetry, U(1)? Or does the Higgs mechanism break the electroweak symmetry into the mass generations, or both? I think you mean that the Higgs breaks things into there mass generations, since the Higgs mechanism determines the mass. Whereas I believe it is the energy level that causes the coupling constants to diverge from their values at the electroweak scale to produce the separate EM and Weak fields.
     
    Last edited: Sep 20, 2013
  15. Sep 21, 2013 #14
    The Higgs breaks the electroweak symmetry by giving mass to the electroweak gauge bosons. Instead of the original massless SU(2) x U(1) gauge bosons, all that's left massless is a new U(1)' gauge boson - I have written in U(1)' because it's different from the original U(1). The original U(1) is the hypercharge boson, but the new U(1) is the photon of electromagnetism.
     
  16. Sep 21, 2013 #15
    The SU(3) ones don't interact with the SU(2) ones, and neither of them interact with the U(1) one.

    SU(3) - g (gluon) - QCD - color
    SU(2) - W - weak isospin
    U(1) - B - weak hypercharge

    The two electroweak ones can be interpreted as W+, W-, W0, and B.

    Their interaction with the Higgs particle is |G.H|2 where

    G = g2 * {{W0, W+}, {W-, -W0}} + g1 * B * {{1,0},{0,1}}

    H = {H+, H0}

    where H+ and H0 are both complex. I'm waving my hands about factors of 2 and the like.

    Due to its self-interaction, |H| becomes nonzero. Its resolution into components is essentially arbitrary, but I'll follow the usual convention and use H = {0, v}, where |H|2 = v2. The observed Higgs particle is a field that gets added to v.

    That turns G.H into {g2*W+, - g2*W0 + g1*B}*v

    and its absolute square into

    (g2*v)2 * (W+*W-) + (g2*W0 - g1*B)2*v2

    The first term gives the mass of the charged W particle: mW = g2*v

    The second term is more complicated, since it mixes the W0 and the B. The mixing angle is called the "Weinberg angle", aW:

    g2 = sqrt(g22 + g12) * cos(aW)
    g1 = sqrt(g22 + g12) * sin(aW)

    Let
    W0 = Z*cos(aW) + A*sin(aW)
    B = - Z*sin(aW) + A*cos(aW)
    A = photon field

    Then the second Higgs-interaction term gives the mass of the Z: mZ = sqrt(g22 + g12) * v

    The photon field drops out, which is why the photon stays massless.
     
  17. Sep 21, 2013 #16
    Let's see what the photon and Z interactions look like. I'll set
    g12 = sqrt(g22 + g12)
    g2 = g12*cos(aW)
    g1 = g12*sin(aW)
    mZ = g12*v

    In general, an interaction between a field and the neutral electroweak gauge particles is
    (I3*g2*W0 + Y*g1*B) * field
    I3 = projected weak-isospin component
    Y = weak hypercharge

    Plugging in the Z-photon resolution:

    g12 * (I3*cos(aW)*(Z*cos(aW) + A*sin(aW)) + Y*sin(aW)*(-Z*sin(aW) + A*cos(aW)))

    The photon interaction is the simplest: g12*cos(aW)*sin(aW)*(I3 + Y) * A

    So the particle's electric charge is Q*e, where
    Q = I3 + Y
    e = g12*cos(aW)*sin(aW)
    is the elementary charge

    This is the same for both left-handed and right-handed parts of elementary fermions, a side effect of how the Higgs mechanism generates mass.

    The Z particle is another story: g12*(I3*cos(aW)2 - Y*sin(aW)2) * Z
    or
    g12*(I3 - Q*sin(aW)2)

    For the elementary fermions, the left-handed part has I3 nonzero but the right-handed part has I3 zero. Writing the left-handed projection operator as (1+h)/2 and the right-handed one as (1-h)/2, with h.h = 1, we get for the interactions:

    Photon:
    e*Q*(1+h)/2 + e*Q*(1-h)/2 = e*Q -- no chirality!

    Z:
    g12*(I3 - Q*sin(aW)2)*(1+h)/2 + g12*( - Q*sin(aW)2)*(1-h)/2 =
    g12*(I3*(1+h)/2 - Q*sin(aW)2)

    Like the charged weak interaction, which is proportional to (1+h)/2, the neutral one is chiral.
     
  18. Sep 22, 2013 #17
    I have to say I don't understand this statement. The link below shows which particles interact with which others.

    http://en.wikipedia.org/wiki/Standard_Model#Gauge_bosons

    If I'm reading this right, quarks, SU(3), interact with weak bosons, SU(2), and weak bosons interact with leptons, U(1). So I assume there is a coupling constant associated with each of these cross-symmetry interactions. I think this means my original question goes unanswered so far: Are the coupling constants associated with the cross-symmetry interactions expressed in terms of the coupling constants associated with intra-symmetry interactions? Or are all the coupling constants simply put in by hand after being determined by experiment without regard to whether there is any kind of relationship between the constants?
     
    Last edited: Sep 22, 2013
  19. Sep 28, 2013 #18
    Hello lpetrich.

    Sorry for the late reply, but I really have to take some time out in understanding the concepts; even I don't know

    whether I have understood it not. 'To err is to human'.


    As per your first posting:

    I am unable to understand the equation R=exp(i*q*a)

    Well, speaking of space-time symmetry, I understand, the 4 areas including the Lorentz boost. For super symmetry,

    SUSY it is that every boson changes into fermions and vice-versa.
     
  20. Sep 28, 2013 #19
    If I don't want to understand the maths part, is it possible to understand what super symmetry is all about?
     
  21. Sep 28, 2013 #20
    I'll give it a shot, but I must warn you I haven't read the other responses so I'm probably being redundant. In Physics there is this theorem, Noether's theorem, which says for each symmetry of your action, the thing that determines the dynamics of your system, you get a conserved charge. For example, if your action has translation symmetry you get conservation of momentum, or if it has rotational symmetry you have conservation of angular momentum and so on. Physicist were interested in all the types of symmetry a physically suitable action could have and have tried to classify them all. These were known as the No Go theorems. The most famous being the one of Coleman and Mandula. Which basically said the only symmetries a physical system could have were the generators of the Poincare group and internal symmetries. There is however one possible extension to this theorem, for point particles, this extension is supersymmetry. In the standard model there are two types of particles fermions and bosons. The fermions are particles of half integer spin and are like electrons, protons, things like that. The bosons are particles with integer spin and are the messenger particles, the particles that send the force messages. These are things like the photon, the graviton, and the gluons. Supersymmetry is a symmetry that exchanges bosonic variables with fermionic ones and vice versa. Physically what this predicts, if it is correct, is that the standard model is only half of the story. For every boson there is a corresponding super partner fermion, sparticle, and vice versa for the fermions.
     
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