Understanding the Center of Mass Energy in Fixed Target vs. Collider Experiments

Click For Summary
SUMMARY

This discussion focuses on deriving expressions for the center of mass energy in fixed target versus collider experiments. In fixed target experiments, the center of mass energy is expressed as \(s=\frac{E_b^2}{c^2}+m_t^2c^2+2E_bm_t-p_b^2\), while in collider experiments, it simplifies to \(s=\frac{(E_A+E_B)^2}{c^2}\). The approximations made in the textbook, such as \(2m^2c^2+2Em\) for fixed targets and \(\frac{4E^2}{c^2}\) for colliders, assume equal masses, specifically \(m_b \approx m_t\) and \(E_A \approx E_B\). The discussion raises questions about the validity of these assumptions in different experimental setups.

PREREQUISITES
  • Understanding of momentum 4-vectors
  • Familiarity with the center of mass energy formula \( \sqrt{s}=\sqrt{(p_1+p_2)^2} \)
  • Basic knowledge of fixed target and collider experimental setups
  • Concept of relativistic energy-momentum relations
NEXT STEPS
  • Research the derivation of center of mass energy in various particle physics experiments
  • Study the implications of mass approximations in high-energy physics
  • Explore the differences between fixed target and collider experiments in detail
  • Learn about the role of energy-momentum conservation in particle collisions
USEFUL FOR

Students and researchers in particle physics, particularly those studying experimental methods and energy calculations in high-energy collisions.

vbrasic
Messages
71
Reaction score
3

Homework Statement


While not explicitly a homework question, I am having some trouble with deriving expressions for the center of mass energy in a fixed target experiment versus a collider experiment. The question is effectively, "Derive an expression for the center of mass energy in a fixed target experiment and compare this to the center of mass energy in a collider experiment."

Homework Equations


The momentum 4-vector. Also, the formula for center of mass energy ##\sqrt{s}=\sqrt{(p_1+p_2)^2}##.

The Attempt at a Solution


For a fixed target experiment, we have the two momentum 4-vectors, ##(\frac{E_b}{c},p_b)##, and ##(m_tc,0)##, for the beam particle and target particle respectively. Then, $$s=\frac{E_b^2}{c^2}+m_t^2c^2+2E_bm_t-p_b^2.$$

We can group the first and last term together to obtain ##m_b^2c^2+m_t^2c^2+2E_bm_t##. However, my textbook at this point claims that this is equivalent to ##2m^2c^2+2Em##. My question is then, would this not only hold true for ##m_b\approx m_t##?

Similarly, for a collider experiment, we have, ##s=(\frac{E_A}{c}+\frac{E_B}{c})^2\rightarrow s=\frac{(E_A+E_B)^2}{c^2}##. Again, my textbook claims that this is equivalent to ##\frac{4E^2}{c^2}##, which again I think, should only hold true for ##E_A\approx E_B##.

If I am not understanding incorrectly, why can these approximations be made?
 
Physics news on Phys.org
They indeed seem to be assuming the masses to be equal.
 

Similar threads

Replies
1
Views
1K
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
17
Views
3K
Replies
4
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K