Understanding the Doppler Effect Equation: Velocity and Frequency Relationship

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Homework Help Overview

The discussion revolves around the Doppler Effect equation, specifically focusing on the relationship between velocity and frequency as a person travels towards a wall while using a tuning fork. Participants are exploring the implications of the observer's and source's velocities in the context of the equation.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are questioning the signs of the observer's and source's velocities in the Doppler Effect equation, particularly when the observer is also the source. There are discussions about treating the wall as a source and the implications of whether the observer is stationary or moving.

Discussion Status

The discussion is ongoing, with participants raising various interpretations of the Doppler Effect. Some have offered insights into the nature of sound waves in different scenarios, while others are seeking clarification on the correct application of the equation. There is no explicit consensus yet on the correct approach.

Contextual Notes

Participants are grappling with the assumption that observers are always stationary, which has been challenged in the context of the problem. The differences in frequency perceived based on the relative motion of the source and observer are also under examination.

dekoi
Suppose a person is traveling towards a wall with a tuning fork at frequency 'f' at a speed of 'v*'. Using the doppler effect equation:
f' \ = \frac{v + v_o}{v - v_s}

What would the sign of v_o and v_s be? I don't understand, since the man is both the observer and the source. (Let - be receeding and + be approaching).
 
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Treat the wall as a source which is approaching the observer. Remember that observers are aways stationary.
 
Integral said:
Remember that observers are aways stationary.

Observers aren't always stationary though. The effect will be different if the wall approaches him than if he approaches the wall.
 
So which is the correct answer??
 
d_leet said:
Observers aren't always stationary though. The effect will be different if the wall approaches him than if he approaches the wall.
Why? (to b, not to a)
 
berkeman said:
Why? (to b, not to a)

Because if the sound is moving then the waves will be closer together or farther apart than if the sound is staionary.
 
No. In an approaching situation, the waves are compressed no matter what.
 
berkeman said:
No. In an approaching situation, the waves are compressed no matter what.

but if f is the frequency of the source.

then f(1+ v/v_sound) is noth the same thing as f/(1 - v/v_sound) the equations are different for each situation so the frequencies heard by the listener will be different in each case.
 

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