Understanding the Doppler Effect: Relative Velocity Calculation Explained

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The discussion clarifies the concept of relative velocity in the context of the Doppler Effect. It explains that when an observer moves away from a wave source, the relative velocity is calculated as (v-u), where v is the wave speed and u is the observer's speed. This is because both the wave and the observer are moving in the same direction, leading to a decrease in the relative speed. If they were moving in opposite directions, the relative speed would be calculated as (v+u). Understanding this distinction is crucial for accurately applying the Doppler Effect in physics.
kelvin macks
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Homework Statement



can anyone explain why reletive velocity is (v-u), based on my understanding, as the obesrvers moving away, the distance of the f th wavefront and first waavefront increases. so i would say it's v+u . correct me if I'm wrong. thanks.

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The distance between wave fronts appears to increase, yes, but that is because the relative speed is also decreasing as the observer accelerates away. If u=v then the wave would never reach you.
 
The wave and the observer are moving in the same direction. Their relative speed is v-u. If they were moving in the opposite direction than the relative speed would be v+u.
 
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If two cars travel on the freeway at similar speeds in the same direction the relative velocity between them is small. It's not going to be the sum of their speeds.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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