Understanding the Equation of Motion in Particle Mechanics: Explained

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Homework Help Overview

The discussion revolves around a problem in particle mechanics involving the equation of motion for a particle attracted to a fixed point by a force that varies inversely with distance raised to the power of n. The original poster expresses confusion regarding the equation of motion and its components, particularly the significance of the symbol used in the equation.

Discussion Character

  • Exploratory, Conceptual clarification

Approaches and Questions Raised

  • The original poster attempts to understand the equation of motion provided, questioning the meaning of the negative sign and the symbol μ. Some participants clarify that μ represents an unknown constant, while others suggest that the equation is more of an illustrative example rather than a reflection of actual physics.

Discussion Status

The discussion is ongoing, with participants providing clarifications about the equation and its components. There is an exploration of the significance of the symbols used, but no consensus on the broader implications of the equation in real-world physics has been reached.

Contextual Notes

The problem appears to be framed as an illustration rather than a practical application, leading to questions about its relevance to actual physics.

I am Meaningless
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Hello everybody, I Am Meaningless and I had this doubt when I was reading some illustrations based on questions in Particle mechanics.


So the Question was,

A particle is attracted by a force to a fixed point varying inversely as (distance)^n. If the velocity acquired in falling from an infinite distance to a distance 'a' from the centre be equal to the velocity acquired in falling from rest from distance 'a' to a distance (1/4)'a', prove that n = (3/2)
As this was an illustration it was natural for me to directly look at the solution given to me below it.
They started the problem like this:

The Equation of motion is

d^2x/dt^2 = -(u)/x^n
where u = meu (symbol) and x (from my observations) = distance covered

I did not understand this and would love it if someone could explain this equation

EDIT: I recognised the fact that
acceleration (inversely proportional) distance ^n
and when I equated would result in a proportionality constant, taken as 'u' and since it was being attracted had the negative symbol on it. But does the symbol have any significance? Any physical values?
 
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I am Meaningless said:
But does the symbol have any significance?
The symbol μ? No, it is just representing an unknown constant.
 
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haruspex said:
The symbol μ? No, it is just representing an unknown constant.
Thanks for your help, just was wondering if perhaps it really was an important equation.
 
I am Meaningless said:
Thanks for your help, just was wondering if perhaps it really was an important equation.
No, it represents the behaviour in this artificial question. It does not correspond to any actual physics of which I am aware.
 
haruspex said:
No, it represents the behaviour in this artificial question. It does not correspond to any actual physics of which I am aware.
Okay, Thanks for your help again![emoji1]
 

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