Understanding the Infinite Set of Reals in Cauchy Convergence Proof

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The discussion focuses on the proof that a Cauchy sequence is convergent, specifically examining the infinite set of reals represented by the condition {x∈ℝ : {n∈ℕ: an≤x} is infinite}. The participants clarify that this set includes all real numbers that are greater than or equal to the terms of the Cauchy sequence for infinitely many indices n. The conclusion drawn is that since aN+1 is included in this set, it confirms that the set is not empty, thereby reinforcing the convergence of the sequence.

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I'm reading the proof that a cauchy sequence is convergent.

Let an be a cauchy sequence and let ε=1. Then ∃N∈ℕ such that for all m, n≥N we have
an-am<1. Hence, for all n≥N we have an-aN<1 which implies an<aN+1. Therefore, the set {n∈ℕ: an≤aN+1} is infinite and thus {x∈ℝ : {n∈ℕ: an≤x} is infinite} ≠ ∅.

I can't make sense of the last set. What does it represent and why is it not empty?
 
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Do you buy the statement that \{n \in \mathbb{N} \colon a_n \le a_N + 1 \} is infinite? If so, what does that tell you about the a_n themselves?
 
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statdad said:
Do you buy the statement that \{n \in \mathbb{N} \colon a_n \le a_N + 1 \} is infinite? If so, what does that tell you about the a_n themselves?

Okay, I get it now. It's the set of all reals that are ≥ an for infinitely many n's. aN+1 is an element in this set, thus it's not empty.
I'm studying independently so I occasionally get stuck trying to figure out easy concepts like this. Thank you!
 

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