Understanding the Kronecker Delta function

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Homework Help Overview

The discussion revolves around understanding the Kronecker Delta function, particularly its properties and implications in the context of Einstein notation. The original poster expresses confusion regarding specific equalities involving the Kronecker Delta, particularly why certain expressions equal three.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to understand the meaning of the Kronecker Delta function and its application in specific equalities. They question the validity of certain expressions and seek clarification on the implications of Einstein notation. Other participants provide corrections and insights regarding the notation and its conventions.

Discussion Status

Participants are actively engaging in clarifying misunderstandings about the Kronecker Delta and its notation. Some have offered corrections to the original poster's statements, while others have provided additional resources and explanations regarding Einstein notation. The discussion appears to be productive, with participants building on each other's contributions.

Contextual Notes

There is a mention of the Einstein summation convention, which may have led to confusion regarding the expressions in question. The original poster's assumptions about the equalities are being examined and questioned by other participants.

Citizen_Insane
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Homework Statement


I'm having some trouble understanding the Kronecker Delta function and how it is used. I understand the basics of it, if i=j, delta=1, if not, delta=0. However, I don't understand why:

\delta_{ii}=3
and
\delta_{ij}\delta_{ij}=3

Homework Equations



\delta_{ij}= \left\{\begin{array}{cc}1,&\mbox{ if }i=j,\\0, & \mbox{ if } i\neq k\end{array}\right.

The Attempt at a Solution



I have not been able to find any proofs using the Kronecker delta online anywhere so I'm not exactly sure of its function. My best guess of why \delta_{ii}=3 would be that you take the determinant of the identity function which would give you three. However, I'm not exactly sure what to do for the second one.

Also could someone explain why \delta_{ii}=\delta_{11}+\delta_{22}+\delta_{33}=1+1+1=3? That's what was in my book but they didn't have any explanation of why.
 
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Citizen_Insane said:
I don't understand why:

\delta_{ii}=3
and
\delta_{ij}\delta_{ij}=3

Where did you find these equalities? They are not correct. I think that they were meant to be these:

\sum_{i = 1}^{3} \delta_{ii}=3
and
\sum_{i = 1}^{3}\sum_{j = 1}^{3} \delta_{ij}=3
 
The sigma summation sign is generally omitted in the Einstein summation convention, antonantal.

The reason is that the sign is entirely superfluous.
 
Thanks guys, that makes perfect sense now. I had forgotten that they could have been in Einstein notation.
 
arildno said:
The sigma summation sign is generally omitted in the Einstein summation convention, antonantal.

The reason is that the sign is entirely superfluous.

I knew about the Einstein notation but I didn't think it was used in the equalities above because the index variable appears only in the subscript position.

According to this convention, when an index variable appears twice in a single term, once in an upper (superscript) and once in a lower (subscript) position, it implies that we are summing over all of its possible values.
 
That depends.

In expressions where there are no possibilities of misunderstanding, why bother make the distinction between subscripts and superscripts?

Just throw that notational element out as well.
 

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