Understanding the Limit of 2 Variables (x,y) -> (0,0) for (x^2)(y)/((x^4)+(y^2))

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SUMMARY

The limit of the function (x^2)(y) / ((x^4) + (y^2)) as (x,y) approaches (0,0) is established to be 0 based on multiple paths of approach. Specifically, evaluating the limit along the paths x_n = 0, y_n = 1/n, x_n = 1/n, y_n = 0, and x_n = y_n = 1/n consistently yields a limit of 0. However, the limit does not exist when considering paths such as y = x^2, which leads to a limit of 1/2. This discrepancy indicates that the limit is path-dependent, confirming that the overall limit does not exist.

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What is:
lim(x,y)->(0,0) of (x^2)(y) / ((x^4) + (y^2)) ?

When I take x_n = 0, y_n = 1/n, lim=0
and x_n = 1/n, y_n = 0, lim=0
and x_n = y_n = 1/n, lim=0
All three limits are zero, yet other people I've asked say the limit doesn't
exist. Am I right, or am I doing something wrong here? Thanks.
 
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[tex]\lim_{(x,y) \rightarrow (0,0)}\frac{x^2y}{x^4+y^2}[/tex][tex]x=0[/tex]
[tex]\lim_{(x,y) \rightarrow (0,0)}\frac{0\cdot y}{0+y^2}=0[/tex][tex]y=0[/tex]
[tex]\lim_{(x,y) \rightarrow (0,0)}\frac{x^2\cdot 0}{x^4+0}=0[/tex][tex]y=x^2[/tex]
[tex]\lim_{(x,x^2) \rightarrow (0,0)}\frac{x^4}{2x^4}=\frac 1 2[/tex]

Aim to make your powers the same, use [tex]y=x^2[/tex] or [tex]x=y^2[/tex].

General tests:

[tex]x=y=0[/tex]
[tex]y=x[/tex]
[tex]x=y^n[/tex]
[tex]y=x^n[/tex]
 
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