Chemistry Understanding the Mechanism of E1 Reaction on Levosalbutamol

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The discussion focuses on the reaction mechanism of levosalbutamol, specifically why the reaction occurs at the hydroxyl group (OH). The participant suggests that the presence of two adjacent pi bonds is a factor, with the OH bond being the most polarized and likely to break, facilitating the formation of a double bond. The stability of the carbocation intermediate is highlighted as a crucial aspect of the mechanism. Additionally, the use of a catalyst in the initial step is recommended, although it may not always be effective. Visual representations of the reaction mechanism are encouraged for further clarity.
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Homework Statement
Where will the E1 reaction occur
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Hi,
I have to determine the reaction mechanism of this molecule.
Can someone please explain to me why the reaction would occur on OH (A)?
Is it bc you can't have 2 pi bonds next to each other and OH(A) is the only polarised bond in the molecule where it would easily break off and form a double bond?
Thank you!
 
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Try drawing the reaction mechanism for each case and see if you can get any further. Unfortunately there’s no great way to do chemical structure drawings in the forum, but feel free to post pictures of your work and I’ll take a look.
 
Hint: The stability of the carbocation intermediate plays a role.
 
A good rule of thumb is to use the catalyst in the first step. Doesn’t always work but it usually does.
 
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