Understanding the Rank of a Matrix: Explained Simply

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The discussion clarifies that the rank of a matrix is determined by the number of non-zero rows, which corresponds to the leading ones in its row echelon form. For the given matrix, the rank is confirmed to be 2, as it has two non-zero rows. The last row does not count as a leading one since it is entirely zero. Additionally, if two rows are identical, they are not linearly independent, resulting in a rank of 1. Understanding these concepts simplifies the process of determining matrix rank.
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Hey I am just wondering about this question... I have reduced it as much as I can and the second part of the question is asking about the rank of the matrix... which means the leading number of ones right?

SO if I had this matrix 2 5 0
0 2 1
0 0 0

Wat would be the leading ones and would the last row be classed as leading ones? If you can just giv a brief explanation that would be great! I understand wat I meant to be finding just am a lil unsure of the concept!

Would the rank be 2?
 
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the matrix was meant to be

2 5 0
0 2 1
0 0 0

sorry if it doesn't look right in the above post!
 
If A = \begin{bmatrix}<br /> 2 &amp; 5 &amp; 0 \\<br /> 0 &amp; 2 &amp; 1 \\<br /> 0 &amp; 0 &amp; 0 \\<br /> \end{bmatrix}

then the rank is 2. The rank is just the number of non-zero rows.
 
ahhh that's easy! Thanks... also just wonderin if you had 2 rows that were identical then the rank would just be 1 right?
 
yes, because they are not linearly independent
 

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