Understanding the Role of the Dirac Delta Function in Multipolar Polarization

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SUMMARY

The discussion focuses on the application of the Dirac Delta Function in calculating the matrix elements <2s | P(r) | 1s> of the microscopic polarization for the hydrogen atom. The integral expression for polarization, P(r) = ∫ dr' r' ρ(r') δ(r - r'), utilizes the Dirac Delta Function to restrict the integration to the point where r' equals r. Participants clarify that the delta function effectively simplifies the integral by nullifying contributions from all other points, leading to a straightforward evaluation of the polarization operator.

PREREQUISITES
  • Understanding of quantum mechanics, specifically hydrogen atom wavefunctions.
  • Familiarity with the Dirac Delta Function and its properties.
  • Knowledge of multipolar polarization concepts in quantum systems.
  • Basic integration techniques in the context of physics.
NEXT STEPS
  • Study the properties and applications of the Dirac Delta Function in quantum mechanics.
  • Explore the concept of multipolar polarization in greater detail.
  • Learn about matrix elements and their significance in quantum mechanics.
  • Investigate the wavefunctions of hydrogen atom states, specifically 1s and 2s.
USEFUL FOR

Students and researchers in quantum mechanics, particularly those studying atomic physics and polarization phenomena, will benefit from this discussion.

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Homework Statement


Using the explicit expression for the mulitpolar polarization, find the matrix elements <2s | P(r) | 1s> of the microscopic polarization between the 1s and 2s states of the hydrogen atom.

Homework Equations


P(r) = \int dr&#039; r&#039; \rho(r&#039;) \delta(r-r&#039;)

I don't understand how the Dirac Delta Function is supposed work? What it is and how does it operate in the intergral?

The Attempt at a Solution


&lt;\psi(2s) | P(r) | \psi(1s) = \int dr&#039; r&#039; \rho(r&#039;) \delta(r-r&#039;)

\psi(1s), \psi(2s) are just H-atom wavefunctions.
 
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I'm not familiar with this operator, but just looking at the equation for P(r) I would read it as rho(r)*r. The delta function restricts the integrand to the point where r' = r, and it's equal to zero for other values of r'.
 
This is easy!
 

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