Prove:( (1 - cos A)/ (1+cos A) ) ^(1/2) = cosec A - cot A
Then they have...
((1 - cos A)/ (1+cos A) ) ^(1/2) = ( (1 - cos A)^2 )/ (1-cos^2 A) ) ^(1/2)
= (1 - cos A) / (1-cos^2 A) ^(1/2)/
I have never done anything like this... I have just been studying trig for the past two days...
Why did they square the entire numerator but only square the cos in the denominator?
... Can some help me understand this the easiest way possible? thank you.
The Attempt at a Solution
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