Understanding the Units in Relativistic Momentum Calculations

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SUMMARY

The discussion centers on calculating the relativistic momentum of an electron moving at 0.600c, specifically in MeV/c units. The user initially calculated the momentum using the electron's mass (9.1E-31 kg) and derived a value of 2.04E-22 kg·m/s. After converting to MeV/c, they realized that converting the mass to MeV/c² first simplifies the unit conversion process. Ultimately, the correct momentum is approximately 0.384 MeV/c, confirming that unit consistency is crucial in relativistic calculations.

PREREQUISITES
  • Understanding of relativistic momentum equations
  • Familiarity with unit conversions between Joules, MeV, and kg·m/s
  • Basic knowledge of special relativity concepts
  • Ability to perform algebraic manipulations involving square roots and fractions
NEXT STEPS
  • Study the derivation of the relativistic momentum formula
  • Learn about the conversion factors between MeV, Joules, and kg·m/s
  • Explore the implications of relativistic effects on particle physics
  • Investigate the role of Lorentz factors in relativistic calculations
USEFUL FOR

Students and professionals in physics, particularly those focusing on modern physics and particle dynamics, will benefit from this discussion. It is also valuable for educators teaching concepts of relativity and momentum in advanced physics courses.

jk4
I was working a problem in a Modern Physics book:
Find the momentum (in MeV/c) of an electron whose speed is 0.600c.

My first approach was:
mass of electron = 9.1E-31 kg

\sqrt{1 - \frac{(0.600c)^{2}}{c^{2}}} = 0.800

p = \frac{9.1E-31 * 0.600c}{0.800} = 2.04E-22 (ignoring units)

then I needed to convert to MeV/c so with some messing around I ended up dividing by 1,000,000 and then multiplying by c to get the exact answer in the book. But this bothered me because I thought I had MeV then multiplying by c to get the answer in the book in MeV/c which doesn't make sense...

I then realized if I first convert the mass into \frac{MeV}{c^{2}} then the units work out perfectly. But I'm still curious why I get the same answer doing it the first way, could someone please help me understand why it works out?
 
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jk4 said:
I was working a problem in a Modern Physics book:
Find the momentum (in MeV/c) of an electron whose speed is 0.600c.

My first approach was:
mass of electron = 9.1E-31 kg

\sqrt{1 - \frac{(0.600c)^{2}}{c^{2}}} = 0.800

p = \frac{9.1E-31 * 0.600c}{0.800} = 2.04E-22 (ignoring units)

then I needed to convert to MeV/c so with some messing around I ended up dividing by 1,000,000 and then multiplying by c to get the exact answer in the book. But this bothered me because I thought I had MeV then multiplying by c to get the answer in the book in MeV/c which doesn't make sense...

I then realized if I first convert the mass into \frac{MeV}{c^{2}} then the units work out perfectly. But I'm still curious why I get the same answer doing it the first way, could someone please help me understand why it works out?
According to this, 1 MeV = 1.60217653 * 10^-13 J (and 1 J = 1 kg * m^2 / s^2). So, 1 MeV/c = (1.60217653 * 10^-13 / 299792458) kg * m / s = 5.34428565 * 10^-22 kg * m / s. And if the mass of an electron is 9.11 * 10^-31 kg, then its momentum at 0.6c is (9.11 * 10^-31 * 0.6 * 299792458 / 0.8) kg * m / s = 2.05 * 10^-22 kg * m / s. This is 0.384 the size of 5.34428565 * 10^-22 kg * m / s which I found above for the value of 1 MeV/c, so the momentum of the electron at 0.6c should be 0.384 MeV/c...is this different from what you got?
 
Last edited:
I got 0.383MeV/c so you that's what I got. I was just confused about how the units worked themselves out in my first method of computing the answer, but thanks to your post I see it.
 
jk4 said:
I got 0.383MeV/c so you that's what I got. I was just confused about how the units worked themselves out in my first method of computing the answer, but thanks to your post I see it.
So is your question from the original post resolved? I was confused about what you meant when you said you divided by 1,000,000 and multiplied by c to get the correct answer, since 2.04*10^-22 * 299792458 / 1,000,000 = 6.12 * 10^-20, which isn't even close to 0.384.
 

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