MHB Understanding the Wronskian Determinant

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Hi guys! How's it going? OK so I'm like totally stuck and I have no idea how to do this. View attachment 4011
 

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The Wronskian of two functions $ f_1$ and $ f_2$ is defined as
\[
W (f_1, f_2 ) =
\left | {\begin{array}{cc}
f_1 & f_2 \\
f_{1}^{'} & f_{2}^{'} \\
\end{array} } \right |
\]
Using this definition, what then is the Wronskian determinant?

Then, if the determinant is never 0 on the interval, the functions are linearly independent.
 
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I have the equation ##F^x=m\frac {d}{dt}(\gamma v^x)##, where ##\gamma## is the Lorentz factor, and ##x## is a superscript, not an exponent. In my textbook the solution is given as ##\frac {F^x}{m}t=\frac {v^x}{\sqrt {1-v^{x^2}/c^2}}##. What bothers me is, when I separate the variables I get ##\frac {F^x}{m}dt=d(\gamma v^x)##. Can I simply consider ##d(\gamma v^x)## the variable of integration without any further considerations? Can I simply make the substitution ##\gamma v^x = u## and then...

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