Understanding Time Constants and the Mathematical Equation for Current Decay

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transgalactic
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i understood every thing except at the last 30 seconds

he says "after 5 time constants t=rc" current will be 0
i can't understand by what mathematical equation he got this number 5
??
 
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intuitively i know that after the capacitor will be filled with charge
it will stop being a conductor

but how he came up with the "5"
??
 
The 5 he choose is an example of a 'magic number'.

We know that current decays as [tex]I = I_{initial} e^{-\frac{t}{R C}}[/tex].

Hence, as time passes, I gets smaller and smaller.

After 1 time constant,
[tex]\frac{I}{I_{initial}} = e^{-1} = 0.368[/tex]
After 2 time constants,
[tex]\frac{I}{I_{initial}} = e^{-2} = 0.135[/tex]
After 3 time constants,
[tex]\frac{I}{I_{initial}} = e^{-3} = 0.050[/tex]
After 4 time constants,
[tex]\frac{I}{I_{initial}} = e^{-4} = 0.018[/tex]
After 5 time constants,
[tex]\frac{I}{I_{initial}} = e^{-5} = 0.007[/tex]

So a more accurate statement is, "After 5 time constants, the current is approximately 0."

He could have easily said 4 or 6 or 100. They key point is that after about 3-5 time constants, the current is effectively 0.

Edit: Formatting error, sorry,
 
Last edited:
Hao said:
The 5 he choose is an example of a 'magic number'.

We know that current decays as [tex]I = I_{initial} e^{-\frac{t}{R C}}[/tex].

Hence, as time passes, I gets smaller and smaller.

After 1 time constant, [tex]\frac{I}{I_{initial} = e^{-1} = 0.368}[/tex]
After 2 time constant, [tex]\frac{I}{I_{initial} = e^{-2} = 0.135}[/tex]
After 3 time constant, [tex]\frac{I}{I_{initial} = e^{-3} = 0.050}[/tex]
After 4 time constant, [tex]\frac{I}{I_{initial} = e^{-4} = 0.018}[/tex]
After 5 time constant, [tex]\frac{I}{I_{initial} = e^{-5} = 0.007}[/tex]

So a more accurate statement is, "After 5 time constants, the current is approximately 0."

He could have easily said 4 or 6 or 100. They key point is that after about 3-5 time constants, the current is effectively 0.
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