Understanding Trig Identities and Variations

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bobsmith76
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Homework Statement



Two integral identities worked out line by line: problem 43 expands the integrand of (sec x + cot x)^2 into sec^2 x + 2 csc x + (csc^2 x - 1), and problem 44 expands (csc x - tan x)^2 similarly, with final results on the right.


I don't see how they're going from

sec x cot x to csc x

and

csc x tan x to sec x

The derivative of sec x is sec x tan x not csc x tan x
and the derivative of csc x is -csc x cot x

and if it's an identity then they didn't care to inform me of that at this website

http://www.sosmath.com/trig/Trig5/trig5/trig5.html
 
bobsmith76 said:

Homework Statement



Two worked integrals: problem 43, integral of (sec x + cot x)^2 dx expanded into sec^2 x + 2 sec x cot x + cot^2 x, equal to tan x - 2 ln|csc x + cot x| - cot x - x + C; problem 44, integral of (csc x - tan x)^2 dx expanded, equal to -cot x - 2 ln|sec x + tan x| + tan x - x + C.


I don't see how they're going from

sec x cot x to csc x

and

csc x tan x to sec x

Express sec x, csc x, cot x and tan x in terms of sin x and cos x first.

The derivative of sec x is sec x tan x not csc x tan x
and the derivative of csc x is -csc x cot x

Sure, but what's the relevance of this? They weren't integrating at that stage, merely simplifying using trig identities.
 
bobsmith76 said:

Homework Statement



Two worked integral expansions, numbered 43 and 44, expanding (sec x + cot x)^2 and (csc x - tan x)^2 into sums of standard integrals with their evaluated antiderivatives below.


I don't see how they're going from

sec x cot x to csc x

and

csc x tan x to sec x

The derivative of sec x is sec x tan x not csc x tan x
and the derivative of csc x is -csc x cot x

and if it's an identity then they didn't care to inform me of that at this website

http://www.sosmath.com/trig/Trig5/trig5/trig5.html
You should not only recognize the trig identities, but different variations of them. For instance,
[itex]\tan \theta = \frac{\sin \theta}{\cos \theta}[/itex].
But it is also true that
[itex]\tan \theta = \sin \theta \sec \theta[/itex].