- #1

NewtonianAlch

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## Homework Statement

[itex]\int[/itex][itex]\frac{sec^{2}x}{tan^{4}x}[/itex]dx

## Homework Equations

## The Attempt at a Solution

I have the answer as -1/3 cot^3(x) + C listed.

All the intermediate steps are given, but the first one is they have converted the sec/tan integral in to:

[itex]\int[/itex]{cot^{2}x}{csc^{2}x} dx

I am a little confused by the trig identities used and manipulated to get this.