Understanding Weights & Roots: Why Does T Act Trivially?

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SUMMARY

The discussion centers on the concept of weight spaces in the context of Lie algebras, specifically focusing on the maximal torus T and its Cartan subalgebra \mathfrak{t}. It establishes that weights are the irreducible representations of T, and when restricting a representation \rho : G \to GL(V) to T, one obtains a direct sum of weights \alpha_i. The trivial action of T on its own tangent space \mathfrak{t} is confirmed, as the adjoint action of T on itself is identity due to T being abelian, leading to the conclusion that while T acts trivially on \mathfrak{h}, its action on the rest of the Lie algebra can be non-trivial, introducing nontrivial weights or roots.

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jdstokes
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I'm having trouble understanding the idea of a weight space.

Suppose \mathfrak{g} is the Lie alebra of G with maximal torus T and Cartan subalgebra \mathfrak{t}. The weights are the (1-dimensional) irreducible represenations of T. If we restrict any representation \rho : G \to GL(V) to T (\rho|_T : T \to GL(V)) then we get a direct sum of weights \alpha_i. If \rho is taken to be the adjoint representation, then the roots are defined to be the nontrivial weights of this rep.

My question concerns the trivial weights. Why exactly is it that T acts trivially on its own tangent space \mathfrak{t}?
 
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I realized that this is pretty obvious since the adjoint action of T on itself is just identity because T is abelian. Thus for any t \in T, the linear transformation Ad|_T (t) : \mathfrak{g} \to \mathfrak{g} acts trivially on the Cartan subalgebra \mathfrak{h}. The T-action on the remainder of the Lie algebra, however may be non-trivial, which is where the nontrivial weights (ie roots) enter.
 

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