Understanding y'=2/3x-1/3(x2-4)+x2/3*2x

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SUMMARY

The discussion centers on the differentiation of the function y=x^(2/3)(x^2-4) and the simplification of its derivative. The initial derivative calculated is y'=2/3x-1/3(x^2-4)+x^(2/3)*2x. The confusion arises regarding the simplification process leading to y'=8x^2-8/3(x^(1/3)). Participants seek clarification on how the numerator and denominator are structured in the final expression, particularly whether 8x^2 - 8 is in the numerator and if both 3 and x^(1/3) are in the denominator.

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Homework Statement


y=x2/3(x2-4)



Homework Equations





The Attempt at a Solution


1.y'=2/3x-1/3(x2-4)+x2/3*2x

2.y'=2x2-8+2x5/2/3(x1/3)

the book agrees with my unsimplified (#1)derivative but it goes further to simplify the equation as
y'= 8x2-8/3(x1/3)

I can't see how they got 2(x2-4)+x2/3*2x to be 8x2-8
in the numerator.
Would someone explain this to me?
 
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It's difficult to tell in your second expression what's in the numerator and what's in the denominator.

Is 8x^2 - 8 in the numerator?
Are both 3 and x^(1/3) in the denominator?

I can't explain it to you if I don't know what you wrote.
 

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