Underwater Pressure sunken ocean liner

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SUMMARY

The discussion centers on calculating the gauge pressure and depth of a sunken ocean liner using the absolute pressure of 413 atmospheres and the density of saltwater at 1025 kg/m³. The gauge pressure is determined by subtracting atmospheric pressure from absolute pressure, resulting in a gauge pressure of 412 atmospheres. The depth of the ocean liner is calculated using the formula P = Dgh, leading to a depth of approximately 4071.8 meters below the water surface.

PREREQUISITES
  • Understanding of pressure concepts, specifically gauge and absolute pressure.
  • Familiarity with the formula P = Dgh for calculating pressure and depth.
  • Knowledge of unit conversions, particularly between atmospheres and Pascals.
  • Basic principles of fluid mechanics, especially in relation to density and pressure in fluids.
NEXT STEPS
  • Study the relationship between pressure and depth in fluids using the hydrostatic pressure equation.
  • Learn about the effects of density variations in different fluids on pressure calculations.
  • Explore advanced applications of gauge pressure in underwater robotics and submersible design.
  • Investigate the implications of pressure on materials used in deep-sea exploration.
USEFUL FOR

This discussion is beneficial for students in physics or engineering, marine researchers, and professionals involved in underwater exploration and robotics.

velvetymoogle
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Homework Statement


While exploring a sunken ocean liner, the principal research found the absolute pressure on the robot observation submarine at the level of the ship to be 413 atmospheres. The density of the surrounding saltwater was 1025kg/m^3. Calculate the gauge pressure on the sunken ocean liner. Calcuate the depth of the sunken ocean liner.


Homework Equations


Pabsolute = Pgauge + Patmosphere
P=Dgh


The Attempt at a Solution


For the gauge pressure, I know that atmospheric pressure is usually 1, but because we are underwater, isn't it a lot higher or is it the force that we feel that's high?
Is it just 413 - 1 = Pgauge?

Also for depth, I know you have to conver 412 atmospheres. Do you multiply it by 1.013x10^5 because that's the conversion factor with meters in it and then just divide by (1025 x -10) to get 4071.8m below the surface of the water?
 
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Indeed; a good idea is to convert things from atmospheres into N / m^2.

Though, you can combine these two equations =).

Gauge pressure excludes atmospheric pressure by the way.
 
No, I know that. That's why I subtracted one. My work is right though, yes?
 
velvetymoogle said:
No, I know that. That's why I subtracted one. My work is right though, yes?

All your work is fine. :smile:
 

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