Are you sure you just don't like it because it contradicts your cherished beliefs?
I'm certain that I don't like it because it contradicts my cherished physics beliefs, and not just because of them either at that!
Here are my corrections and comments to ohwilleke lastpost, I given a mistake score for each error, but I haven't totalled them. It's pretty clear we've got self proclaimed physics god here, a college level guy who towers above the physics world, 100% confident he's perfect. no need for a degree in physics eh ohwilleke?
Infinite and instanteneous fields are a product of Newtonian theory,
They are not a 'product' of Newtonian theory, they ARE newtowian theory. Don't add unnessacery words to try and sound clever. Keep it as simple as possible. 1/5
but not of more advanced classical theories
ok.
(theories which are strictly deterministic and non-quantum and presume a "smooth" space are called "classical theories").
ok. people often like to classify relativity theory as a classical theory, but since it was invented the same time as quantum theory, it's a slightly confusing classifcation. Best to just classify it as deterministic and non-quantum.
General relativity, which is a classical theory (although it is also a post-Newtonian theory) when taken together with the Big Bang Theory, is not an infinite field theory. The universe it proposes is closed and has a radius of 15 billion light years give or take.
Here is one of your key misunderstandings. In GR theory the universe has no set radius, it is variable over time, you know this. You state 15 billion light years as the radius because that is the current radius of the light shell. However, this light shell radius will continue to increase with no bound. In maths, infinite series are named as such because they have no last element and extend infinitely, even though every element can be assigned a real number. To suggest that a series is not infinite because a given element is not infinite is incorrect. You are suggesting GR is not an infinite field theory because the current radius of the light shell is not infinite, you are wrong. 5/5
Quantum theory is also not an infinite field theory. It has fields that likewise propogate at the speed of light and the time that has been available for those fields to propogate is finite.
Wrong for same reason. I guess in which ever GR book you have read, the distinction between instaniously infinite and infinite given infinite time was stressed. This does not mean fields that reach infinitely given infinite time are not infinite. Any object affected by the former type of field, will also be affected by the latter.
Also your notion that even an infinite field theory with instantenous effect would necessarily lose energy does not follow.
1. Sorry but it does, and it's not my notion. Never mind your argument about the energy intergral, it misses the problem completely. You happily go ahead with integrating a force field, without stating by what construction mechanism this force field has come into existence. You need to ask "How does the force from one body get to another?" By bus? by magic? No, the current model states by messenger particle. For electromagnetism for example, the messenger particle is the photon. In every electro-magnetic interaction, a number of photons sent from one body exert force via their electromagnetic fields on their arrival at the other body. When you calcuate an electromagnetic force on a body you are calculating the electromagnetic force of the photons that happen to have just arrived at a given instance of time. When you do your integration over space, you are just summing the energys of all the messenger particles in a given volume of space.
You intergrate a force field. But you have no regard for what you are integrating - traveling quanta. Photons have energy. By the currrent model, these quanta can be sent in certain directions so that travel away from the material universe forever. Thus the universe is losing energy. 5/5
your notion that even an infinite field theory with instantenous effect
2. I have not stated a specific type of infinite field being nessacery for what I saying. This is your fabrication. This is your fixation on the distinction between GR and Newtonian grav, and lack of understanding of types of infinite fields coming into play again. 3/5
The total energy of an infinite field is the integral of its potential from the object to infinity.
ok, as long as you mean the 'object' is the source of the force field.
For a well behaved field function (such as Newtonian gravity), this integral has a finite value
Ha! One day, if you ever aqquire some maths skill, you might want to actually calculate an inverse square infinite force field integral. Watch out, the answer might upset you. You might consider going to the math help forum and getting tom's help. 5/5
In the mean time, consider the photons the sun emits in one second. Consider the space in a one light second radius sphere around the sun. In this shell is 1 light seconds worth of photons. You can then wrap this 1 light second shell in another shell 2 light seconds from the sun, then another 3 light seconds etc... in each one of these 'layers' is 1 unit of photons. Summing these to infinity : 1+1+1+1+... = infinity. Infinite photons have a sum energy of infinity.
I expect your incorrect belief spans from what you've read about line integrals in inverse square force fields , i.e. the integrals of paths of particles in inverse square force fields, which are not infinite.
and the difference between the total value of the integral and the value of the integral out to a radius R becomes infintessimally small in the limit as R becomes arbitrarily large.
sorry, but you can't blindly rely on the assitotion to zero of inverse proportion to stop it's integral from diverging.
e.g. integrate 1/r with limits infinity to 1. answer = Log infinity - Log 1 = infinity - 0.
4/5
Observations show there is a large amount of gravity force unacounted for in the classical, infinite space, model.
No such observations exist.
Good grief, I don't believe it. This coming from a person who supports MOND. If no such observation exists why have physicists been working on dark matter theories for 30 years? Trying to find their lost black socks in deep space? duh. Galaxy rotation curves. 5/5 + 5 for self contradiction.
The difference in the amount of Newtonian graviational potential accounted for in a field with 15 billion light years diameter for the largest known objects (e.g. galactic clusters) and the amount of gravitational potential accounted for in a field of infinite diameter is on a percentage basis so tiny that humans have no instruments with sufficient precision to measure them, even if there was some way that this could be achieved.
Again, only correct again if your considering only line integrals in inverse square force fields. Although by now, I'm thinking it's more luck than understanding when you get it right. Your statement actually supports my argument. If we have no way of telling, then why are we so sure of the current theory?
General relativity doesn't really presume any medium.
plainly wrong. Space is a medium, and you know it. 5/5
Anyway. I just wanted to go on about a simple thought experiment in finite space with a very simple immediate consequence.
1.Consider a finite space universe with just 1 body of matter ( any scale ). If this bodies emits radiation, then since the universe is closed the radiation must return to the body.
This does not follow. To take a fairly simple example for purposes of proof by contradiction, suppose that your universe has the topology of a torus.
You've misunderstood what I mean by closed, probably because you have only read and know of one notion of closed space, the one used in GR. spactial closure. I'm talking about energy closure. i.e. the universe is a closed energy system, no energy gets in or out. 3/5
Suppose further that the radiation gets into an outer loop around the torus while your black body stays on an inner loop around the torus. The radiation need never return to the black body.
No. Only if you model the light to be an infinitely thin line, which is pretty bad modeling. If it has any width, it will eventually go through space it's already been through. But this is irrelavent, since your argument is already dead. 4/5
Alternately, suppose that your closed universe has dimensions 100 billion light years in radius. Suppose further that all mass in your closed universe is located at point A in the center of the universe and that the mass began emitting radiation 15 billion light years ago.
ok, but this argument is dead.
There is no reason for the radiation to have returned to the center of the universe
You haven't stated a dynamic for when the radiation hits the edge of the universe. Either it bounces or it doesn't. If it bounces, then it will get back to the centre eventually. 4/5
and there is no way that any observer within the 15 billion light year radius could be aware that it might ever do so.
You haven't considered the possibility of a bouncing dynamic, in which case an observer could be aware of the radiation if he was around 200 billion years after the radiation was sent . 1/5
Your argument doesn't work, and is completely misdirected. 5/5
2.Consider if the body emits mass . As long as this emitted mass doesn't interact with, in any way, the original mass, then it could be expected to behave like a wave in accordance with quantum theory. Since the universe is closed, and assuming the wave cannot collapse upon itself, then wave will collapse back onto the original mass.
Again, this does not follow due to similar reasoning.
Wrong, due to your same misunderstanding about closure. 1/5
Also, at the universe type scales your are talking about the expectation that an emitted mass would exhibit strong wavelike behavior is unreasonable and does not flow from quantum theory.
I didn't state a scale. That I stated a cosmological size scale is your fabrication. 4/5
There is no known mass upper bound where the wave aspect of matter becomes theorectically impossible. Most physicists believe a mass of any size will exhibit wave properties given the right circumstances; i.e. no contact with radition that would give away it's state to another piece of matter. The practical limiting factor on Earth is that larger objects are harder to absolutely sheild from radiation. In deep space there is little radiation, so it can be expected bodys may exhibit slighty more wave nature than when close to other mass. But this is speculative and has been for decades, and was partly what I was speculating on in my inital posts. 4/5
3. Now consider a closed universe with two bodies of matter. ( kept in particle behaviour by repeated interaction with each other ). If one of the bodies emits radiation ( separate from the repeated interaction energy transfer already mentioned ) then since the universe is closed, this radiation can only end up on one of the two bodies.
No. The radiation can spend forever between the two bodies unless you are proposing a very small two node universe.
I would not have believed someone who has college level physics believes this, staggering. Plainly wrong. 5/5
(or at least for all time that has passed to date)
This statement signifys your at least vaguely aware of your shambles logic of falsehoods and mistakes.
1. I was not talking about reality ( the real universe ). I was talking about a hypothetical universe. The date in reality has no bearing whatsoever on my thought experiment. 4/5
2. It seems you are still thinking about your 100 billion light year radius spatially closed universe, and your arguments that it is closed based on the fact the light shell has only traveled a finite distance. What if you allow more time than has pasted to date? 4/5
3. It totally contracdicts the conclusion in your last statement. It seems you know you wrong, but you can't bring yourself to fully admit it, to me or to yourself. 5/5 + 2 for self contradiction