Uniform Acceleration Homework: Calculate Distance and Force

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SUMMARY

The discussion focuses on calculating the distance a baseball accelerates before release and determining the force exerted by a pitcher. The baseball, weighing 1.40 N, is accelerated to a velocity of 37.0 m/s over a duration of 0.0500 seconds. To find the distance, participants suggest using the kinematic equation v = a t and applying Newton's 2nd law for force calculations. The conversation clarifies that the ball starts from rest, and the instantaneous velocity is achieved at the moment of release.

PREREQUISITES
  • Understanding of kinematic equations, specifically v = a t
  • Knowledge of Newton's 2nd law of motion
  • Familiarity with concepts of acceleration and force
  • Basic grasp of physics terminology related to motion
NEXT STEPS
  • Research kinematic equations for uniformly accelerated motion
  • Study applications of Newton's 2nd law in various scenarios
  • Explore examples of calculating average speed and distance
  • Investigate the relationship between force, mass, and acceleration
USEFUL FOR

Students in physics, particularly those studying mechanics, as well as educators and anyone involved in teaching or learning about motion and forces.

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Homework Statement


After uniformly accelerating his arm for 0.0500 s, a pitcher releases a baseball of weight 1.40 N with a velocity of 37.0 m/s horizontally forward. The ball starts from rest. (Assume that horizontally forward and upward are positive.)


Homework Equations



a)Through what distance does the ball accelerate before its release?

b)What force does the pitcher

The Attempt at a Solution



I got part of part b What force does the pitcher ___Ni + 1.4Nj

I really just need the equation to find part a.
 
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Does
v = a t[/itex]<br /> ring a bell? Can you apply that here? <br /> <br /> Also, the phrases &quot;... with a velocity of 37.0 m/s horizontally forward.&quot; and &quot;The ball starts from rest. &quot; sound a bit contradictory to me (I assume they mean: it starts from rest, <i>then</i> the pitcher accelerates it, and when he let&#039;s go, it has a(n instantaneous) velocity of 37.0 m/s).
 
CompuChip said:
Does
v = a t[/itex]<br /> ring a bell? Can you apply that here? <br /> <br /> Also, the phrases &quot;... with a velocity of 37.0 m/s horizontally forward.&quot; and &quot;The ball starts from rest. &quot; sound a bit contradictory to me (I assume they mean: it starts from rest, <i>then</i> the pitcher accelerates it, and when he let&#039;s go, it has a(n instantaneous) velocity of 37.0 m/s).
<br /> <br /> I tried that but when I input the answer into the site it says it&#039;s wrong.
 
What did you try? You need to find the distance it traveled during its acceleration. Start by finding the average speed.
 
I think what compuchip gave you was the final velocity, after the release. From there you can find the acceleration, having the duration (time) of acceleration. then relating that final result to the change in position in the x direction using your kinematic equations to represent mathematically what is going on physically. Having just the equation never really helped me understand how to use them or when to use them.
 
Ok I understood what you guys said and got part a but I'm still sort of confused about part b, the first part of it.
 
Apply Newton's 2nd law.
 

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