Uniform distribution of a disc

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Homework Help Overview

The discussion revolves around finding the marginal probability density functions (pdf) for a uniform distribution defined over a disc of radius 1 in the plane. The original poster presents the joint pdf and seeks assistance in deriving the marginal pdfs for the variables x and y.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the joint pdf and the method of obtaining marginal densities through integration. Questions arise regarding the appropriate limits of integration for the marginal pdf of x, with suggestions to visualize the unit circle to determine possible y-values for a fixed x.

Discussion Status

There is an ongoing exploration of the correct limits for integration to find the marginal pdfs. Some participants have proposed specific limits, while others encourage further examination of the problem through visualization. No consensus has been reached yet.

Contextual Notes

Participants are considering the constraints of the unit circle and the implications of fixing one variable while integrating out the other. The discussion reflects uncertainty about the correct bounds for integration.

mathmathmad
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Homework Statement



Consider a disc of radius 1 in the plane D in R
D = {(x,y) in R | x^2+y^2 <= 1}
write the marginal pdf of x and y

Homework Equations


The Attempt at a Solution


so the joint pdf is 1/Pi for x^2 + y^2 <= 1 <- correct?
but how to I get the marginal pdfs?
 
Last edited:
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You have

<br /> f(x,y) = \frac 1 \pi<br />
as the joint density. As in every case the marginal density of one variable is found by integrating out the other. Suppose you want the marginal density of x - you need to integrate out y.

<br /> g(x) = \int_a^b \frac 1 \pi \, dy<br />

The question is: what should you use for the limits a and b?
Draw the unit circle and see the set of y-values that are possible when x is fixed.
 
a=0
b=sqrt (1 - x^2) ?
 
mathmathmad said:
a=0
b=sqrt (1 - x^2) ?

Try again. Did you draw the picture?
 
a = - sqrt (1 - x^2)
b = sqrt (1 - x^2)

or should it be -1 to 1
 

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