What is the area of the sector cut out by two rays in a disc with a given area?

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SUMMARY

The problem involves calculating the area of a sector in a disc with an area of 60 in², defined by two rays forming a 60-degree angle. The correct area of the sector is determined to be 10 in², as the area of a sector is calculated using the formula A = (θ/360) * πr². Given that the area of the disc is 60 in², the radius can be derived, leading to the conclusion that the book's answer of 1 in² is incorrect.

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  • Ability to manipulate algebraic expressions to solve for radius and area.
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Homework Statement


Let Rpq be a ray:

.-------.---------------->
p q

draw a second ray Rpm s.t the angle <QPM has 60 degrees

Let D be a disc centered at P and assume its area is 60 in^2. find the area of the sector in the disc cut out by the two rays

Homework Equations

The Attempt at a Solution


I got 10 in^2 my book is telling me 1 in^2.
 
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Book seems wrong. A 60 degree wedge should have 1/6 the area of the circle.
 
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