Unit Conversion - Flux Densities

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SUMMARY

The discussion focuses on converting flux density from Jy (Jansky) to fλ in units of erg s^-1 cm^-2 A^-1. The initial value provided is fv = 1.0254e-2 Jy, and the conversion utilizes the equation fλ = fv * c / λ², where c is the speed of light. A critical point raised is the necessity of knowing the specific wavelength for accurate conversion, as the conversion assumes a wavelength of 1 Å, which is likely incorrect. The final calculated value for fλ was 3.0762e-7 erg s^-1 cm^-2 A^-1, but this was deemed incorrect due to the assumption about the wavelength.

PREREQUISITES
  • Understanding of flux density and its units (Jy)
  • Knowledge of the conversion between frequency and wavelength (c = λν)
  • Familiarity with the equations for flux density conversion (fλ = fv * c / λ²)
  • Basic grasp of astronomical magnitudes and their zero points
NEXT STEPS
  • Research the concept of flux density in astrophysics and its applications
  • Learn about the significance of wavelength in photometric measurements
  • Study the V band wavelength and its relevance in magnitude calculations
  • Explore online tools for unit conversion in astrophysics
USEFUL FOR

Astronomy students, astrophysicists, and anyone involved in photometric measurements and flux density calculations will benefit from this discussion.

deedsy
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Homework Statement


I need to convert from a fv in units of Jy to fλ in units of erg s^-1 cm ^-2 A^-1

fv = 1.0254e-2 Jy


Homework Equations


fv dv = fλ dλ
fλ = fv dv/dλ
and because v = c/λ...

fλ = fv*c / λ^2

Also 1 Jy = 10^-23 erg cm^-2 s^-1 Hz ^-1

The Attempt at a Solution



fλ = [(1.0254e-2 Jy)(10^-23 erg cm^-2 s^-1 Hz ^-1) (3e10 cm/s)(1A/10^-8 cm)] / [1 A^2]

*note: A = angstrom units

my final answer was fλ = 3.0762e-7 erg s^-1 cm^-2 A^-1

But I checked my answer on an online converter and it was wrong, but I don't know why because all my units canceled out correctly.
 
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You have done the conversion as though your given fv was measured at a wavelength of 1A. I doubt this is the case. When you put in the c/λ^2 factor, you need to do it at the wavelength (frequency) of the measurement. Was this given?
 
phyzguy said:
You have done the conversion as though your given fv was measured at a wavelength of 1A. I doubt this is the case. When you put in the c/λ^2 factor, you need to do it at the wavelength (frequency) of the measurement. Was this given?

The first part of the question had us convert a magnitude (12) into fv given a zero point for the magnitude system (fv=647 Jy). So I used m-m0 = -2.5 (f/f0) to solve for f where m0 = 0 and f0 = 647 Jy and m =12. This gave a value of fv = 1.0254e-2 Jy. Then we just have to convert that value into fλ

Here's the question as it appears on the assignment:
Given that the zeropoint of the magnitude system is fv=647 Jy. Find the flux density of a 12th magnitude star in Janskeys (which is in fv) and then convert it to fλ (in units of ergs^-1cm^-2A^-1)(ignore any minus signs in the conversion).That's all the information I have.
 
Well, I may be wrong, but I think you have to assume some wavelength to do the conversion. If they are visible magnitudes, I would use the center of the V band, which is at 0.55 μm.
 
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