Master Conversions: How to Convert Units for Newtons | Conversions Homework Help

[Makali]

Homework Statement

I am trying to figure out how to convert some units to get an end result of Newtons.

Homework Equations

The equation that I need to use is density of water * volume of displaced water * g

The Attempt at a Solution

The density of water is 1g/cm³ * 60mL/cm³ * 9.81 m/s²

How do I convert these in order for the end result to become Newtons?

Thanks

 

[lekh2003]

Convert everything to SI units. That would require some conversions. SI system, is kilograms, meters, seconds and liters.

Once you are done with the calculation, look at the units and convert everything to SI system.

EDIT: I don't think liters is SI, try and convert that to $m^3$.

 

[Orodruin]

To add a bit more, the easiest way of doing unit conversions is to start multiplying by ones. Not to solve your original problem for you, imagine that you want to convert 591 g cm^2/s^2 to Joules, the SI unit for energy. You can do this by multiplying by 1 = (1 J)/(1 kg m^2/s^2) and treating all the units as if they were numbers and group them with the same type of units (i.e., lengths, times, etc). You would find
\begin{align*}
591~\frac{\rm g\, cm^2}{\rm s^2} &= 591~\frac{\rm g\, cm^2}{\rm s^2} \cdot \frac{1~\rm J}{1~\frac{\rm kg\, m^2}{\rm s^2}} \\
&= 591~{\rm J} \cdot \frac{\rm g}{\rm kg} \left(\frac{\rm cm}{\rm m}\right)^2 \\
&= 5.91\cdot 10^2~{\rm J} \cdot 10^{-3} \cdot (10^{-2})^2 \\
&= 5.91 \cdot 10^{-5}~{\rm J}.
\end{align*}
We have here also used that 1 cm = 0.01 m and that 1 g = 0.001 kg. You can do a similar thing with your unit conversion.