Unit vectors in polar co ordinates

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SUMMARY

The discussion focuses on the properties of radial and tangential unit vectors in polar coordinates, specifically their dependence on the scalar variable θ, which represents the angle between the position vector and the polar axis. It emphasizes the necessity of transforming these unit vectors into Cartesian coordinates (i, j) for calculating velocity and acceleration magnitudes. This transformation simplifies the computation by allowing the use of the Pythagorean theorem, as opposed to the more complex metric tensor required in polar coordinates.

PREREQUISITES
  • Understanding of polar coordinates and their representation
  • Familiarity with unit vectors and their properties
  • Knowledge of Cartesian coordinates and vector components
  • Basic concepts of velocity and acceleration in physics
NEXT STEPS
  • Study the transformation of coordinates from polar to Cartesian systems
  • Learn about the metric tensor and its application in different coordinate systems
  • Explore the derivation of velocity and acceleration in polar coordinates
  • Investigate the geometric interpretation of unit vectors in various coordinate systems
USEFUL FOR

Students and professionals in physics, mathematics, and engineering who are working with polar coordinates, particularly those involved in dynamics and vector analysis.

manimaran1605
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I have two questions
1) How the radial and traversal unit vectors are vector funcitons of scalar variable θ (angle between the position vector and polar axis.
2) To find velocity and acceleration in polar co ordinates why it is need to write the traversal and radial unit vectors by transforming its basis to cartesian co ordinate basis i,j? I have little bit idea that it is for our convenience that we are transforming basis to simplify the problem to get the velocity, but i don't know tell how it is convenient
 
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manimaran1605 said:
I have two questions
1) How the radial and traversal unit vectors are vector functions of scalar variable θ (angle between the position vector and polar axis.
2) To find velocity and acceleration in polar co ordinates why it is need to write the traversal and radial unit vectors by transforming its basis to cartesian co ordinate basis i,j? I have little bit idea that it is for our convenience that we are transforming basis to simplify the problem to get the velocity, but i don't know tell how it is convenient

Answering #2 first: We're trying to calculate the magnitude of the velocity and acceleration vectors, and it's really easy to calculate the magnitude of a vector if you know its components in the Cartesian basis: ##S=\sqrt{x^2+y^2}##. If you have the components in a different basis such as polar coordinates, you can still calculate the magnitude but you have to use a thing called the "metric tensor" - you can't just use the simple Pythagorean theorem - and that's often just as much or more work than converting into Cartesian coordinates. (Actually, there's nothing special about Cartesian coordinates, it just so happens that the metric tensor in that coordinate system is so trivial that you don't notice it).

And for #1: the unit vector in the ##r## direction at a point is a unit vector in the direction that ##\theta## is not changing, and the unit vector in the ##\theta## direction is a unit vector pointing in the direction that ##r## is not changing. These vectors will point in different directions at different points in the plane, but their components in the ##(r,\theta)## basis will not; the vectors are ##(1,0)## and ##(0,1)## everywhere when using polar coordinates.
 

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