Unitary spacetime translation operator

omephy
Messages
17
Reaction score
0
Srednicki eqn. (2.23) and (2.24) states: We can make this a little fancier by defining the unitary spacetime translation operator

[tex]T(a) \equiv \exp(-iP^\mu a_\mu/ \hbar)[/tex]

Then we have
[tex]T(a)^{-1} \phi(x) T(a) = \phi(x-a)[/tex]

How do we get the second equation from the first equation?
 
Physics news on Phys.org
If you believe eq. (2.22) just above this, then you can plug ##\phi(x) = e^{-iPx/\hbar}\phi(0)e^{+iPx/\hbar}## into eq. (2.24). Then using the definition of ##T(a)## you can verify that eq. (2.24) holds.
 
Lovely answer.
 

Similar threads

  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 14 ·
Replies
14
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 4 ·
Replies
4
Views
3K