Universal gravitation 7- determine the gravitational force of attraction

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SUMMARY

The gravitational force of attraction between Michael and Elaine, with masses of 75.0 kg and 55.0 kg respectively, and separated by a distance of 2.50 m, is calculated using Newton's Universal Law of Gravitation. The formula applied is F = Gm1m2/d², where G is the gravitational constant (6.67 x 10-11 N*m²/kg²). The resulting force is determined to be 4.4022 x 10-8 N. The calculations have been verified as correct by forum participants.

PREREQUISITES
  • Understanding of Newton's Universal Law of Gravitation
  • Familiarity with gravitational constant (G = 6.67 x 10-11 N*m²/kg²)
  • Basic algebra for solving equations
  • Knowledge of mass and distance in gravitational calculations
NEXT STEPS
  • Explore advanced applications of Newton's Universal Law of Gravitation
  • Learn about gravitational force calculations in different contexts, such as celestial mechanics
  • Study the implications of gravitational force in orbital dynamics
  • Investigate the relationship between gravitational force and weight on Earth
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Students studying physics, educators teaching gravitational concepts, and anyone interested in understanding the fundamentals of gravitational attraction and its calculations.

dani123
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Homework Statement



Michael has a mass of 75.0 kg and Elaine has a mass of 55.0 kg. If Michael and Elaine are 2.50 m apart from each other as they sit in their Physics class, determine the gravitational force of attraction between them.

Homework Equations


I have made a list of equations that are relevant for this entire module on universal gravitation. So although there are many of them does not mean that they all apply in this circumstance. The ones relevant to this question will be placed in bold.

Kepler's 3rd law: (Ta/Tb)2=(Ra/Rb)3

motion of planets must conform to circular motion equation: Fc=4∏2mR/T2

From Kepler's 3rd law: R3/T2=K or T2=R3/K

Gravitational force of attraction between the sun and its orbiting planets: F=(4∏2Ks)*m/R2=Gmsm/R2

Gravitational force of attraction between the Earth and its orbiting satelittes: F=(4∏2Ke)m/R2=Gmem/R2

Newton's Universal Law of Gravitation: F=Gm1m2/d2

value of universal gravitation constant is: G=6.67x10-11N*m2/kg2

weight of object on or near Earth: weight=Fg=mog, where g=9.8 N/kg
Fg=Gmome/Re2

g=Gme/(Re)2

determine the mass of the Earth: me=g(Re)2/G

speed of satellite as it orbits the Earth: v=√GMe/R, where R=Re+h

period of the Earth-orbiting satellite: T=2∏√R3/GMe

Field strength in units N/kg: g=F/m

Determine mass of planet when given orbital period and mean orbital radius: Mp=4∏2Rp3/GTp2


The Attempt at a Solution


So we know the following
m1=75kg
m2=55 kg
d=2.5 m
G=6.67x10-11 N*m2/kg2
F=?

So with the equation highlighted above I solved for F=4.4022x10-8N

I would love for someone to verify my work done on this problem and let me know if i made any mistakes and point them out to me, it would be greatly appreciated! Thanks so much in advance :)
 
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Your work is correct, again.


PS : You don't need to post all obviously simple questions to verify. Be confident that you've done 'em right! :wink:[/size]
 
thanks! I just feel better knowing that I am doing it right, taking physics through correspondence isn't always easy haha
 

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