Universal gravitation 11- determine the gravitational force of attraction

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Homework Help Overview

The discussion revolves around a problem involving universal gravitation, specifically calculating the gravitational force of attraction between two bags of apples after a change in their masses. The original scenario describes two bags, each containing 20 apples, and the gravitational force experienced between them when separated by a distance of 25.0 cm. The problem changes when 10 apples are transferred from one bag to the other.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the correct setup of gravitational force equations, questioning the masses involved and the implications of transferring apples between bags. There is a focus on the relationships between the forces before and after the transfer of apples.

Discussion Status

Participants are actively engaging with the problem, attempting to clarify the equations and relationships between the forces. Some have provided guidance on how to set up the equations, while others are exploring the implications of the mass changes on the gravitational force. There is an ongoing examination of the assumptions made in the problem setup.

Contextual Notes

There is uncertainty regarding the masses of the apples and how they affect the gravitational force calculations. The original poster's initial calculations are questioned, and participants are encouraged to reconsider their approach without relying on numerical substitutions for certain variables.

dani123
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Homework Statement



Two bags of apples, each containing 20 apples of equal mass, experience a gravitational force of attraction of 200 units when separated by a distance of 25.0cm. If 10apples are removed from one bag and placed into the other bag, and the two bags are separated by the same 25.0 cm distance, determine the gravitational force of apples now. Note that the magnitude of the gravitational force should be expressed in units.

Homework Equations



I have made a list of equations that are relevant for this entire module on universal gravitation. So although there are many of them does not mean that they all apply in this circumstance. The ones relevant to this question will be placed in bold.

Kepler's 3rd law: (Ta/Tb)2=(Ra/Rb)3

motion of planets must conform to circular motion equation: Fc=4∏2mR/T2

From Kepler's 3rd law: R3/T2=K or T2=R3/K

Gravitational force of attraction between the sun and its orbiting planets: F=(4∏2Ks)*m/R2=Gmsm/R2

Gravitational force of attraction between the Earth and its orbiting satelittes: F=(4∏2Ke)m/R2=Gmem/R2

Newton's Universal Law of Gravitation: F=Gm1m2/d2

value of universal gravitation constant is: G=6.67x10-11N*m2/kg2

weight of object on or near Earth: weight=Fg=mog, where g=9.8 N/kg
Fg=Gmome/Re2

g=Gme/(Re)2

determine the mass of the Earth: me=g(Re)2/G

speed of satellite as it orbits the Earth: v=√GMe/R, where R=Re+h

period of the Earth-orbiting satellite: T=2∏√R3/GMe

Field strength in units N/kg: g=F/m

Determine mass of planet when given orbital period and mean orbital radius: Mp=4∏2Rp3/GTp2

The Attempt at a Solution


Fg=200N
d=25cm=0.25m

I used Fg=(6.67X10-11)(30)(10)/(0.25)2=3.2X10-7N

I have a strong feeling this answer is wrong, but if someone could point me in the right direction it would be greatly appreciated! Thank you so much in advance.
 
Last edited:
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Your feeling is correct :-p

First off, you do not know the mass of apples in each bag, so your equations are incorrect.

Let the mass of 10 apples be m, the mass of 20 would be 2m. Now set up an equation for both bags,

F_{1} = \frac{G\cdot 2m\cdot 2m}{r^2}

Try making a similar equation for the 10 apple case. Now without the need to substitute the values of G and r, as they remain same, just divide the equations to get an equation for F2.
 
You were told that 10 apples were removed from one bag. But you were not told that they were transferred to the other bag.
 
why is it 2m*2m? I am confused
 
grzz the question actually did state that they were transferred into the other bag, I just edited the problem! Thanks for noticing
 
dani123 said:
why is it 2m*2m? I am confused

I explained why in my previous post... The mass of one 20 apple-bag is 2m, the mass of the other 20 apples bag is 2m. What would the gravitational force between them be(without substituting numerical values)??
 
F=4.2688x10-9*m2?
 
dani123 said:
F=4.2688x10-9*m2?

Uhh I asked without substituting the numerical values, its easier that way :wink:
 
Last edited:
I left m for the mass... but I used the value for G and r...
 
  • #10
so you mean like 4m2=F1*r2/G?
 
  • #11
dani123 said:
so you mean like 4m2=F1*r2/G?

Yes! Can you make a similar equation for the case with 10 and 30 apple-bags?
 
  • #12
3m2=F2*r2/G for the second?

But do I use 200N for the force in both equations to determine the mass?
 
  • #13
dani123 said:
3m2=F2*r2/G for the second?

Yep. :approve:

But do I use 200N for the force in both equations to determine the mass?

Nope. You don't need to find the mass. You need to find the force F2, which ofcourse is not equal to 200N(F1). Try dividing the equations and see how you can find F2..
 
  • #14
dividing the F1 equation by the F2 equation?
 
  • #15
dani123 said:
dividing the F1 equation by the F2 equation?

Yes... :rolleyes:
 
  • #16
F2=266.67 N? Does this seem right?
 
  • #17
dani123 said:
F2=266.67 N? Does this seem right?

Nope. Recheck your equations. What expression did you get after division?
 
  • #18
3/4=F1/F2... because everything else canceled out
 
  • #19
dani123 said:
3/4=F1/F2... because everything else canceled out

Umm no. Without much trouble, that should be 4/3=F1/F2, don't you think? :wink:
 
  • #20
ops haha so the answer should be 150 N right?
 
  • #21
dani123 said:
ops haha so the answer should be 150 N right?

Aye! :approve:
 
  • #22
Thank you so much!
 

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