1. The problem statement, all variables and given/known data Two bags of apples, each containing 20 apples of equal mass, experience a gravitational force of attraction of 200 units when separated by a distance of 25.0cm. If 10apples are removed from one bag and placed into the other bag, and the two bags are separated by the same 25.0 cm distance, determine the gravitational force of apples now. Note that the magnitude of the gravitational force should be expressed in units. 2. Relevant equations I have made a list of equations that are relevant for this entire module on universal gravitation. So although there are many of them does not mean that they all apply in this circumstance. The ones relevant to this question will be placed in bold. Kepler's 3rd law: (Ta/Tb)2=(Ra/Rb)3 motion of planets must conform to circular motion equation: Fc=4∏2mR/T2 From Kepler's 3rd law: R3/T2=K or T2=R3/K Gravitational force of attraction between the sun and its orbiting planets: F=(4∏2Ks)*m/R2=Gmsm/R2 Gravitational force of attraction between the Earth and its orbiting satelittes: F=(4∏2Ke)m/R2=Gmem/R2 Newton's Universal Law of Gravitation: F=Gm1m2/d2 value of universal gravitation constant is: G=6.67x10-11N*m2/kg2 weight of object on or near Earth: weight=Fg=mog, where g=9.8 N/kg Fg=Gmome/Re2 g=Gme/(Re)2 determine the mass of the Earth: me=g(Re)2/G speed of satellite as it orbits the Earth: v=√GMe/R, where R=Re+h period of the Earth-orbiting satellite: T=2∏√R3/GMe Field strength in units N/kg: g=F/m Determine mass of planet when given orbital period and mean orbital radius: Mp=4∏2Rp3/GTp2 3. The attempt at a solution Fg=200N d=25cm=0.25m I used Fg=(6.67X10-11)(30)(10)/(0.25)2=3.2X10-7N I have a strong feeling this answer is wrong, but if someone could point me in the right direction it would be greatly appreciated! Thank you so much in advance.