Universal law of gravitation(variables)

  • Thread starter Thread starter captainsmith1
  • Start date Start date
  • Tags Tags
    Law Universal
AI Thread Summary
To determine the radius of a new planet with twice the mass of Earth but the same gravitational acceleration, the universal law of gravitation is applied. The equation F=G(m1m2/r^2) is manipulated to relate the masses and radii of both planets. Since both planets experience the same gravitational acceleration, their mass and radius relationship can be established. The solution involves equating the gravitational forces and solving for the radius in terms of Earth's radius. Ultimately, the radius of the new planet can be expressed in relation to Earth's radius.
captainsmith1
Messages
6
Reaction score
0

Homework Statement


A planet has twice the mass of earth, but both planets share the same acceleration of gravity. The radius of the new planet in terms of the radius R of Earth is...?


Homework Equations


F=G(m1m2/r2), G being the universal gravitation constant


The Attempt at a Solution


i think you have to manipulate the equation in some way but i can't figure out what to do first.
 
Physics news on Phys.org
From N's law, you have:

<br /> G\frac{Mm}{r^2} = ma_g<br />

Because Earth and planet have same acceleration of gravity => a_g(E) = a_g(P) => relationship between masses and radii => radius of planet.
 
thanks, i understand now
 
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Thread 'Struggling to make relation between elastic force and height'
Hello guys this is what I tried so far. I used the UTS to calculate the force it needs when the rope tears. My idea was to make a relationship/ function that would give me the force depending on height. Yeah i couldnt find a way to solve it. I also thought about how I could use hooks law (how it was given to me in my script) with the thought of instead of having two part of a rope id have one singular rope from the middle to the top where I could find the difference in height. But the...
Back
Top