tim9000 said:Homework Statement
I know the area of a right angled triangle, I also know the ratio of the two non-hypotenuse sides.
Is there anyway of finding the lengths?
pasmith said:If the sides are [itex]a[/itex] and [itex]b[/itex] then you know that the area of the triangle is [itex]\frac12 ab[/itex].
HallsofIvy said:If you call the two legs a and b then the area is (1/2)ab= A so ab= 2A.
The ratio of the two sides is a/b= r so that a= br. Replace a in the first equation by that: ab= (br)b= rb^2= A so b^2= A/r. Solve for b, then solve for a.
To find the missing side length of a triangle, you can use the formula A = 1/2 * b * h, where A is the area, b is the base length, and h is the height. You can also use trigonometric ratios (sin, cos, tan) to find the missing side length.
Yes, as long as you have at least one side length and the corresponding angle, you can use trigonometric ratios to find the missing side length. If you only have the area and internal angles, you may need to use the formula A = 1/2 * b * h to find the missing side length.
If you have multiple missing side lengths, you will need to use the formula A = 1/2 * b * h to find the missing side length. You may also need to use trigonometric ratios to find the remaining side lengths.
It is recommended to start by finding the base length using the formula A = 1/2 * b * h. Then, use trigonometric ratios to find the remaining side lengths in any order.
Yes, as long as you have at least one side length and the corresponding angle, you can use trigonometric ratios to find the missing side length. If you only have the area and one internal angle, you may need to use the formula A = 1/2 * b * h to find the missing side length.