What is the Specific Heat Capacity of the Unknown Material?

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SUMMARY

The specific heat capacity of an unknown material can be determined using the principle of heat transfer, specifically through the equation Q = mcΔT. In this scenario, a 50g sample heated to 80°C is placed in a calorimeter containing 100g of water at 10°C, resulting in a temperature increase of 5°C for the water. The heat capacity of the calorimeter is 20 J/K, which must also be accounted for in the calculations to find the specific heat capacity of the unknown material.

PREREQUISITES
  • Understanding of thermodynamics principles, specifically heat transfer.
  • Familiarity with the equation Q = mcΔT for calculating heat transfer.
  • Knowledge of calorimetry and its applications in measuring heat capacities.
  • Basic algebra skills for manipulating equations and solving for unknowns.
NEXT STEPS
  • Study the concept of calorimetry in detail, focusing on heat transfer calculations.
  • Learn how to apply the equation Q = mcΔT in various scenarios involving different materials.
  • Explore the specific heat capacities of common materials for comparison.
  • Investigate the impact of heat capacity of calorimeters on experimental results.
USEFUL FOR

Students studying physics or chemistry, educators teaching thermodynamics, and anyone involved in experimental heat transfer analysis.

noobatphysics
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Homework Statement


In order to find the specific heat capacity of an unknown material,
a 50g piece is heated to 80 degrees Celsius and fully immersed in a well
insulatyed calorimeter filled with 100g of water at 10 degrees Celsius raising the temperature of the water by 5 degrees, the heat capacity of the calorimeter is 20 J K-1


Homework Equations


MC delta T = MC delta T ?




The Attempt at a Solution


no idea to be honest
at first i thought i can just use Q=mc delta T to do this but i don't know what Q is :S
 
Physics news on Phys.org
The final temperature of substance is same as that of water. You could still use the eqn. you wrote.
 

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