Unraveling the Mystery Behind Quadratic and Linear Simultaneous Equations

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SUMMARY

The discussion focuses on solving simultaneous equations involving both linear and quadratic forms, specifically the equations x + y = 1 and x² + y² = 16. The user expresses confusion regarding the simplification of the quadratic equation 2x² - 2x - 15 = 0, particularly the division by 2 that results in x² - x - 15 = 0. The user questions whether the constant term -15 should also be divided by 2, indicating a misunderstanding of the division process in algebraic equations. The consensus is that the book's explanation is correct, as only the coefficients of the terms are divided, not the constant term.

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  • Learn about the methods for solving simultaneous equations, including substitution and elimination
  • Explore the concept of polynomial division and its applications in algebra
  • Review common mistakes in algebraic simplification to avoid confusion
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david18
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I'm currently going through some questions and came across quadratic and linear simultaneous equations.

Solve the equation: x + y = 1
x^2 + y^2 = 16

I am not interested in the question itself but rather the explanation the book gives me which says after a couple of steps shows the equation:

2x^2 - 2x -15 = 0

Then it tells me to divide the equation by 2 and says when you divide the equation by 2 you will get:

x^2 - x - 15 = 0

I'm confused because i thought the -15 would also have to divide by two...
is it the book or am i missing something serious here?
 
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If the equation you have provided is right, then it is an error on the part of the author/editor/printer.
 

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