Undergrad Unsure of solution to improper integral

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The discussion revolves around solving the improper integral ∫[∞][1] ln(x) x^-1 dx. The original poster struggled with using the comparison test for divergence and initially miscalculated the limits, leading to confusion about the result being ∞. Participants suggested calculating the integral from 1 to Y, then taking the limit as Y approaches infinity to demonstrate that the integral diverges. They confirmed that finding an answer of ∞ is sufficient to prove divergence without needing the comparison test. The conversation emphasizes the importance of correctly applying limits in evaluating improper integrals.
Satirical T-rex
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I've been trying to solve this improper integral ∫[∞][1] ln(x) x^-1 dx. I couldn't find any way to use the comparison test to find divergence, so I used substitution and got ∞-∞ which I was pretty sure was divergence until I noticed I put 0 instead of 1 making my answer ∞. Do I need to prove divergence with a comparison test or is an answer of ∞ enough to prove it.
 
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Hi T, :welcome:
You could work out $$\int_1^Y {\ln x\over x} dx $$ (As I think you did already) and take ##\lim Y\rightarrow \infty## to show the integral does not exist.
 
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Hi,this integral has simple antiderivative (after substituting ##\ln##), after you can take the limit of the result for ##Y\rightarrow +\infty## (as suggested by @BvU ).
 
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Thanks for your help and the warm welcome.
 
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