Update To My Problem On Vectorcalculus

  • Thread starter Thread starter Lisa...
  • Start date Start date
Click For Summary
SUMMARY

The discussion focuses on the motion of a particle in circular motion, specifically analyzing the relationship between angular velocity and linear velocity using vector calculus. The velocity vector is derived from the cross product of angular velocity, represented as w = (d(theta)/dt) k, and position vector r = x i + y j + z k. The resulting expression for velocity, v = (d(theta)/dt) * x j - (d(theta)/dt) * y i, confirms that the velocity vector is tangent to the circle, with its modulus given by |\vec{v}| = (d(theta)/dt) R, where R is the radius of the circle.

PREREQUISITES
  • Understanding of vector calculus, particularly cross products
  • Familiarity with angular velocity and its representation
  • Knowledge of circular motion principles
  • Basic proficiency in mathematical notation and operations
NEXT STEPS
  • Explore the derivation of the cross product in vector calculus
  • Learn about the implications of angular velocity in different coordinate systems
  • Investigate the properties of tangent vectors in circular motion
  • Study the relationship between angular displacement and linear displacement
USEFUL FOR

Students and professionals in physics, particularly those studying mechanics and dynamics, as well as anyone interested in the mathematical foundations of motion in circular paths.

Lisa...
Messages
189
Reaction score
0
A particle moves in a circle that is centered at the origin. The particle has position r and angular velocity w. The velocity v is given by:

v = w x r (with x = the cross product).

My question is, when I calculate this crossproduct with

w= (d(theta)/dt) k and
r= x i + y j + z k

it gives:

(d(theta)/dt) * x j - (d(theta)/dt) * yi

Why does this denote the velocity?
 
Physics news on Phys.org
Compute its modulus and see whether you can find

[tex]|\vec{v}|=\frac{d\theta (t)}{dt} R[/tex]

,where R is the circle's radius.

Daniel.

BTW, you can check whether that vector is always tangent to the circle by dotting it with [itex]\vec{r}[/itex].
 
Thanks I get it now :)
 

Similar threads

Replies
1
Views
1K
Replies
16
Views
3K
Replies
3
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 17 ·
Replies
17
Views
2K
Replies
1
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 15 ·
Replies
15
Views
2K
Replies
12
Views
2K