Calculating Upward Support Force on a Rigid Beam

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The discussion focuses on calculating the upward support force exerted by support 1 on a 3.0-meter-long rigid beam with a mass of 100 kg, supported at both ends. The weight of the student, calculated as 784 N, and the weight of the beam, 980 N, are critical in determining the forces involved. The correct method involves summing the moments around the supports, leading to an upward force of 751.33 N exerted by support 1 after accounting for the weight of both the student and the beam.

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A 3.0-m-long rigid beam with a mass of 100 kg is supported at each end. A
80 kg student stands 2.0 m from support 1. How much upward force does support 1 exert on the beam?

I first found the weight of the student to be 784N.
so 784N*2cm =F*3cm
F= 522.67N
is this right?
 
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No, its not. I think you forgot to take the moment caused by the weight of the beam.
I think this is how it should be done:
(2x784)+(1.5x980) = 3xF
This gives us the value of F(Force on the other support)=1012.67N
Substracting this value from the total downward force(784N+980N) we get the upward force exerted by the support1 be 751.33N
 
DeathKnight said:
No, its not. I think you forgot to take the moment caused by the weight of the beam.
I think this is how it should be done:
(2x784)+(1.5x980) = 3xF
This gives us the value of F(Force on the other support)=1012.67N
Substracting this value from the total downward force(784N+980N) we get the upward force exerted by the support1 be 751.33N


Yes, I forgot to consider the weight of the beam.
Thanks.
 

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