Max Load Force on Uniform Pine Beam of 3.6m & 25kg | Safety Factor 5.0

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SUMMARY

The discussion focuses on calculating the maximum load force (FL) that can be exerted by two vertical roof supports on a uniform pine beam measuring 3.6 meters in length and weighing 25 kg. The beam's cross-section is 9.5 cm x 14 cm, and a safety factor of 5.0 is applied to ensure structural integrity. The formula used is F = 1/5 x A x Maximum stress, where the safety factor indicates that the beam can withstand five times the expected load without failure. Understanding the safety factor is crucial for determining the load limits of structural components.

PREREQUISITES
  • Basic knowledge of structural engineering principles
  • Understanding of safety factors in engineering
  • Familiarity with load calculations and stress analysis
  • Knowledge of material properties, specifically for pine wood
NEXT STEPS
  • Research the concept of safety factors in structural design
  • Learn about calculating maximum load forces on beams
  • Study the properties of pine wood and its stress limits
  • Explore beam support configurations and their effects on load distribution
USEFUL FOR

Engineering students, structural engineers, and anyone involved in designing or analyzing wooden structures will benefit from this discussion.

Neon32
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Homework Statement


A uniform pine beam, 3.6 m long and 9.5 cm x 14 cm in cross section, rests on two supports near its ends, as shown. The beam’s mass is 25 kg and two vertical roof supports rest on it, each one-third of the way from the ends. What maximum load force FL can each of the roof supports exert without shearing the pine beam at its supports? Use a safety factor of 5.0.

Homework Equations

The Attempt at a Solution



Answer sheet:
F= 1/5 x A x Maximum stress

I just don't understand the first step. Why did I multiply it by 1/5? And what does safety factor mean?
 
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Safety factor is how many times stronger the member is than it needs to be.
 

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