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## Homework Statement

A 5m metal beam is supported on 2 supports. The beam is 30kg and the man is 65kg. The man stands at A, to prevent the beam tipping extra weights have been placed at B. Find reaction forces and the weights that have been placed at B. Take acceleration due to gravity to be 9.8ms

## Homework Equations

Force * Distance

Sum of Clockwise = Sum of Anti-Clockwise

Sum of Downward Forces = Sum of Upward Forces

## The Attempt at a Solution

Decorator - 637N

Beam - 294N

F

_{1}being the first support reaction force

F

_{2}being the second reaction force

W being the extra weights added

F

_{1}+ F

_{2}= 931 + W (Sum of up and down)

3F

_{1}+ F

_{2}= 3601.5 (sum of clockwise/anticlockwise)

I have attempted so many different ways to figure this out, but I have no idea how to get around having 3 unknowns at a time. When I take a moment around one of the supports, I have the reaction force the other plus the weight being placed at B. I'm not sure if I'm missing something obvious or not.

Thanks in advance for literally any help