How to Calculate Upward Force on Each Anchorage?

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SUMMARY

The discussion focuses on calculating the upward force on each anchorage for a steel pipeline submerged in water. The internal diameter of the pipeline is 120 cm, and the external diameter is 125 cm, with a steel density of 7900 kg/m³. The buoyancy force per meter run is calculated to be approximately 1.204 x 104 N/m. To determine the upward force on each anchorage, one must subtract the weight of the pipeline per unit length from the buoyancy force, considering the effective length of the pipeline supported by each anchor.

PREREQUISITES
  • Understanding of buoyancy principles and Archimedes' principle
  • Knowledge of weight calculation for cylindrical objects
  • Familiarity with basic physics equations related to forces
  • Ability to visualize and analyze physical scenarios (e.g., drawing diagrams)
NEXT STEPS
  • Calculate the weight of the steel pipeline per unit length using its dimensions and density
  • Learn about equilibrium conditions in physics to understand forces acting on submerged objects
  • Explore the concept of effective length in anchoring systems
  • Investigate how to calculate total forces required for multiple anchorage points
USEFUL FOR

This discussion is beneficial for engineering students, physics enthusiasts, and professionals involved in pipeline design and anchoring systems, particularly those working with submerged structures in fluid environments.

ZeroFive
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Homework Statement



A steel pipeline carrying gas has an internal diameter of 120 cm and an external diameter of 125 cm. It is laid across the bed of a river, completely immersed in water and is anchored at intervals of 3 m along its length.

  1. Calculate the buoyancy force per meter run.
  2. Upward force on each anchorage.

Density of steel = 7900 kg/m3.

2. Equations used

Buoyancy Force = Weight of the displaced fluid volume

The Attempt at a Solution



I calculated that the buoyancy per unit length is (approximately), 1.204 x 104 N/m
But I don't see a way to find the answer to the second question. Can someone lead me in the right direction or show me how it's done?
 
Last edited:
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Welcome to PF!
ZeroFive said:
I calculated that the buoyancy per unit length is (approximately), 1.204 x 104 N/m
OK
But I don't see a way to find the answer to the second question. Can someone lead me in the right direction or show me how it's done?
My hint for this part is to think about whether the weight of the pipe is important in answering the second question.
 
TSny said:
My hint for this part is to think about whether the weight of the pipe is important in answering the second question.

By finding the weight of a unit length and subtracting that from the answer of part 1 gives the additional downward force per unit length the anchor need to provide for the pipe to be in equilibrium. But don't we need the length of the pipe to determine the number of anchors and the total downward force required?
 
ZeroFive said:
By finding the weight of a unit length and subtracting that from the answer of part 1 gives the additional downward force per unit length the anchor need to provide for the pipe to be in equilibrium.
OK
But don't we need the length of the pipe to determine the number of anchors and the total downward force required?
The pipe is anchored every 3 m. Draw a picture and think about the effective length of the pipe that each anchor must hold down.
 

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