Uranium density in fuel meat/kernel

AI Thread Summary
The discussion centers on calculating the fuel density for KLT-40S neutronic simulations, specifically addressing the uranium density in the fuel meat/kernel, which is noted to be 4.5 g/cm3. Participants clarify that this value refers to uranium density rather than UO2 density, which is 10.9 g/cm3, and discuss the implications of the uranium being dispersed in an aluminum-silicon alloy. A method to calculate the overall fuel density using the rule of mixtures is proposed, where the effective density of the UO2 in the dispersion is estimated to be around 5.1 g/cm3. The conversation highlights the importance of clear communication in engineering to avoid misinterpretations that could affect design and manufacturing processes. Overall, the thread emphasizes the need for accurate density calculations in nuclear fuel applications.
nuclearsneke
Messages
15
Reaction score
5
TL;DR Summary
Tl;dr - why is it so low and how to get the right value of density?
Howdy partners!

I am currently doing some project on Klt40s neutronic simulation (you might have heard of Akademik Lomonosov, the floating npp). But I have encountered a problem with fuel density. The only info that i got that "uranium density IN FUEL MEAT/KERNEL" is 4.5 g/cm3. The Fuel is uranium dioxide dispersed in aluminum-silicon alloy.

However, I need the fuel density for further calculations of nuclear densities (1/cm3).
I know that density of uo2 is 10.9 g/cm3 and density of the alloy is around 2.7 g/cm3. Have you guys gotten any ideas on how to calculate the whole fuel density and maybe fractions of fuel and matrix (sial alloy) from these data?
 
Engineering news on Phys.org
Alex A said:
Seems to be quite a lot of detail in this document. https://aris.iaea.org/PDF/KLT-40S.pdf

Maybe that will help.
I hab this one but no luck :(
 
nuclearsneke said:
Summary:: Tl;dr - why is it so low and how to get the right value of density?

"uranium density IN FUEL MEAT/KERNEL" is 4.5 g/cm3.
That is the uranium density, as opposed to UO2 density correct?

And is it 14% enriched?

The density would be low because the U, in the form of UO2, is dispersed in Al-Si alloy.
 
  • Like
Likes nuclearsneke
Astronuc said:
That is the uranium density, as opposed to UO2 density correct?

And is it 14% enriched?

The density would be low because the U, in the form of UO2, is dispersed in Al-Si alloy.
I get it that density of fuel would be low due to its dispersion in alloy. But is there any way to calculate a density of fuel pellet starting from this "uranium density in fuel kernel" value?
 
nuclearsneke said:
is there any way to calculate a density of fuel pellet starting from this "uranium density in fuel kernel" value?
Well, assuming that the 'uranium density' refers to uranium with ρ = 4.5 g/cm3, then the UO2 density in the dispersion would be ~5.1 g/cm3, based on 0.8814 gU/gUO2.

For a given volume V of dispersion, the mass of the volume would be xV*ρ(UO2)+(1-x)V*ρ(Al) = M with a volume V and density D=M/V of the dispersion ( x = volume fraction of UO2), assuming that there is no interaction between UO2 and Al. The total mass M = m(UO2) + m(Al).

The mass of UO2 in the dispersion is simply xV*ρ(UO2) and the effective density is just x*ρ(UO2) = 5.1 g/cm3, and so x = 0.465, based on ρ(UO2) = 10.96 g/cm3.

This is basically an application of 'rule of mixtures', or 'law of mixtures'.
https://link.springer.com/referenceworkentry/10.1007/978-1-4419-6247-8_6810
https://www.sciencedirect.com/topics/engineering/rule-of-mixture-equation
 
Last edited:
  • Informative
  • Like
Likes berkeman and nuclearsneke
Astronuc said:
Well, assuming that the 'uranium density' refers to uranium with ρ = 4.5 g/cm3, then the UO2 density in the dispersion would be ~5.1 g/cm3, based on 0.8814 gU/gUO2.

For a given volume V of dispersion, the mass of the volume would be xV*ρ(UO2)+(1-x)V*ρ(Al) = M with a volume V and density D=M/V of the dispersion ( x = volume fraction of UO2), assuming that there is no interaction between UO2 and Al. The total mass M = m(UO2) + m(Al).

The mass of UO2 in the dispersion is simply xV*ρ(UO2) and the effective density is just x*ρ(UO2) = 5.1 g/cm3, and so x = 0.465, based on ρ(UO2) = 10.96 g/cm3.

This is basically an application of 'rule of mixtures', or 'law of mixtures'.
https://link.springer.com/referenceworkentry/10.1007/978-1-4419-6247-8_6810
https://www.sciencedirect.com/topics/engineering/rule-of-mixture-equation
Wow. Given that I had a material science course mostly focused on phase diagrams and lattice types, I have never heard of that preem law/rule of mixture. Now the problem I mentioned above looks so trivial... Thank you, Astronuc!
 
  • Like
Likes anorlunda and berkeman
nuclearsneke said:
Given that I had a material science course mostly focused on phase diagrams and lattice types, I have never heard of that preem law/rule of mixture.
Well, I had much the same experience. I didn't hear about the 'rule/law of mixtures' until I encountered in the job. I've done similar problems in the past. It can be tricky. In this problem, one must assume no chemical interaction between the UO2 and Al-Si-alloy, which is a reasonable assumption if done at low temperature, which it usually is. Basically one would mix powders and cold press them between layers of Al-Si. Also, one must be clear on the problem statement, which is why I asked about the density of uranium vs uranium dioxide. Things can go wrong when there is miscommunication between design and manufacturing, or between engineering groups.
 
  • Like
Likes nuclearsneke
Back
Top