Uranium density in fuel meat/kernel

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SUMMARY

The discussion focuses on calculating the effective fuel density of uranium dioxide (UO2) dispersed in an aluminum-silicon alloy for the KLT-40S neutronic simulation project. The uranium density in the fuel kernel is specified as 4.5 g/cm³, while the UO2 density is 10.9 g/cm³. Participants confirm that the lower density is due to the dispersion of UO2 in the alloy and suggest using the rule of mixtures to derive the effective density of the fuel pellet, which is approximately 5.1 g/cm³. Key calculations involve determining the volume fraction of UO2 in the mixture.

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  • Understanding of nuclear fuel composition, specifically uranium dioxide (UO2) and aluminum-silicon alloy.
  • Familiarity with density calculations and the concept of volume fractions.
  • Knowledge of the rule of mixtures in material science.
  • Basic principles of neutronic simulation relevant to nuclear reactors.
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  • Research the rule of mixtures in material science for composite materials.
  • Study the properties and applications of uranium dioxide (UO2) in nuclear fuel.
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  • Investigate the KLT-40S reactor design and its operational parameters.
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Nuclear engineers, material scientists, and researchers involved in the design and analysis of nuclear fuel systems, particularly those working with uranium dioxide and aluminum-silicon alloy composites.

nuclearsneke
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TL;DR
Tl;dr - why is it so low and how to get the right value of density?
Howdy partners!

I am currently doing some project on Klt40s neutronic simulation (you might have heard of Akademik Lomonosov, the floating npp). But I have encountered a problem with fuel density. The only info that i got that "uranium density IN FUEL MEAT/KERNEL" is 4.5 g/cm3. The Fuel is uranium dioxide dispersed in aluminum-silicon alloy.

However, I need the fuel density for further calculations of nuclear densities (1/cm3).
I know that density of uo2 is 10.9 g/cm3 and density of the alloy is around 2.7 g/cm3. Have you guys gotten any ideas on how to calculate the whole fuel density and maybe fractions of fuel and matrix (sial alloy) from these data?
 
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nuclearsneke said:
Summary:: Tl;dr - why is it so low and how to get the right value of density?

"uranium density IN FUEL MEAT/KERNEL" is 4.5 g/cm3.
That is the uranium density, as opposed to UO2 density correct?

And is it 14% enriched?

The density would be low because the U, in the form of UO2, is dispersed in Al-Si alloy.
 
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Astronuc said:
That is the uranium density, as opposed to UO2 density correct?

And is it 14% enriched?

The density would be low because the U, in the form of UO2, is dispersed in Al-Si alloy.
I get it that density of fuel would be low due to its dispersion in alloy. But is there any way to calculate a density of fuel pellet starting from this "uranium density in fuel kernel" value?
 
nuclearsneke said:
is there any way to calculate a density of fuel pellet starting from this "uranium density in fuel kernel" value?
Well, assuming that the 'uranium density' refers to uranium with ρ = 4.5 g/cm3, then the UO2 density in the dispersion would be ~5.1 g/cm3, based on 0.8814 gU/gUO2.

For a given volume V of dispersion, the mass of the volume would be xV*ρ(UO2)+(1-x)V*ρ(Al) = M with a volume V and density D=M/V of the dispersion ( x = volume fraction of UO2), assuming that there is no interaction between UO2 and Al. The total mass M = m(UO2) + m(Al).

The mass of UO2 in the dispersion is simply xV*ρ(UO2) and the effective density is just x*ρ(UO2) = 5.1 g/cm3, and so x = 0.465, based on ρ(UO2) = 10.96 g/cm3.

This is basically an application of 'rule of mixtures', or 'law of mixtures'.
https://link.springer.com/referenceworkentry/10.1007/978-1-4419-6247-8_6810
https://www.sciencedirect.com/topics/engineering/rule-of-mixture-equation
 
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Astronuc said:
Well, assuming that the 'uranium density' refers to uranium with ρ = 4.5 g/cm3, then the UO2 density in the dispersion would be ~5.1 g/cm3, based on 0.8814 gU/gUO2.

For a given volume V of dispersion, the mass of the volume would be xV*ρ(UO2)+(1-x)V*ρ(Al) = M with a volume V and density D=M/V of the dispersion ( x = volume fraction of UO2), assuming that there is no interaction between UO2 and Al. The total mass M = m(UO2) + m(Al).

The mass of UO2 in the dispersion is simply xV*ρ(UO2) and the effective density is just x*ρ(UO2) = 5.1 g/cm3, and so x = 0.465, based on ρ(UO2) = 10.96 g/cm3.

This is basically an application of 'rule of mixtures', or 'law of mixtures'.
https://link.springer.com/referenceworkentry/10.1007/978-1-4419-6247-8_6810
https://www.sciencedirect.com/topics/engineering/rule-of-mixture-equation
Wow. Given that I had a material science course mostly focused on phase diagrams and lattice types, I have never heard of that preem law/rule of mixture. Now the problem I mentioned above looks so trivial... Thank you, Astronuc!
 
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nuclearsneke said:
Given that I had a material science course mostly focused on phase diagrams and lattice types, I have never heard of that preem law/rule of mixture.
Well, I had much the same experience. I didn't hear about the 'rule/law of mixtures' until I encountered in the job. I've done similar problems in the past. It can be tricky. In this problem, one must assume no chemical interaction between the UO2 and Al-Si-alloy, which is a reasonable assumption if done at low temperature, which it usually is. Basically one would mix powders and cold press them between layers of Al-Si. Also, one must be clear on the problem statement, which is why I asked about the density of uranium vs uranium dioxide. Things can go wrong when there is miscommunication between design and manufacturing, or between engineering groups.
 
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