Use dimensional analysis to show that increase in g due to lead

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cloudone
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Homework Statement


A clock is placed on a floor covered with lead density [tex]\rho[/tex] and thickness d. Use dimensional analysis to show that increase in gravitational field strength at the clock dueo to the layer of lead is proportional to [tex]Gd\rho[/tex]

Homework Equations


The Attempt at a Solution


to show that [tex]\Delta g = kGd\rho[/tex]

units of [tex]\Delta g = m s^{-2}[/tex]

units of [tex]Gd\rho = m^{3}kg^{-1}s^{-2}kgm^{-3}[/tex]

I don't get why they're not the same.
 
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cloudone said:

Homework Statement


A clock is placed on a floor covered with lead density [tex]\rho[/tex] and thickness d. Use dimensional analysis to show that increase in gravitational field strength at the clock dueo to the layer of lead is proportional to [tex]Gd\rho[/tex]


Homework Equations





The Attempt at a Solution


to show that [tex]\Delta g = kGd\rho[/tex]

units of [tex]\Delta g = m s^{-2}[/tex]

units of [tex]Gd\rho = m^{3}kg^{-1}s^{-2}kgm^{-3}[/tex]

I don't get why they're not the same.

You forgot to include the units for d, the thickness.
 
Stonebridge said:
You forgot to include the units for d, the thickness.

argh, thanks. I just realized that. I've been thinking dp as differential of p