Use KCL to solve a Very simple electrical circuit

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SUMMARY

This discussion focuses on applying Kirchhoff's Current Law (KCL) to solve a simple electrical circuit problem. Given the currents I0 = -2 A, I1 = -4 A, Is = 8 A, and voltage Vs = 12 V, the participant successfully calculated the unknown currents. The calculations revealed I2 = 6 A and I3 = 2 A, demonstrating the effective use of KCL in circuit analysis.

PREREQUISITES
  • Understanding of Kirchhoff's Current Law (KCL)
  • Basic knowledge of electrical circuit components
  • Familiarity with current and voltage measurements
  • Ability to analyze circuit nodes and branches
NEXT STEPS
  • Study advanced applications of Kirchhoff's Laws in complex circuits
  • Learn about Ohm's Law and its integration with KCL
  • Explore circuit simulation tools like LTspice for practical analysis
  • Investigate the impact of resistors on current flow in circuits
USEFUL FOR

Students studying electrical engineering, educators teaching circuit analysis, and hobbyists interested in understanding basic electrical circuits.

qpham26
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Homework Statement



Given
I0=-2 A
I1=-4 A
Is= 8 A
Vs= 12 V

Find all the unknown currents.

http://sphotos-a.xx.fbcdn.net/hphotos-snc7/398253_493549703997883_2004542070_n.jpg

Homework Equations



Kirchhoff’s current law

The Attempt at a Solution


I start at node a and found I2= 6 A
and then from R2 follow the current to find out that

Is= I3 + I2 = 8A => I3= 2 A

thanks for your time.
 
Last edited by a moderator:
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qpham26 said:

Homework Statement



Given
I0=-2 A
I1=-4 A
Is= 8 A
Vs= 12 V

Find all the unknown currents.

http://sphotos-a.xx.fbcdn.net/hphotos-snc7/398253_493549703997883_2004542070_n.jpg

Homework Equations



Kirchhoff’s current law

The Attempt at a Solution


I start at node a and found I2= 6 A
and then from R2 follow the current to find out that

Is= I3 + I2 = 8A => I3= 2 A

thanks for your time.
Yes.
 
Last edited by a moderator:

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