Simple Electrical Equation Advice.

  • Thread starter Thread starter MathsRetard09
  • Start date Start date
  • Tags Tags
    Electrical
Click For Summary

Homework Help Overview

The discussion revolves around finding the current in each resistor of a parallel circuit with given resistances and voltage. The resistors are specified as R1 = 1kOhms, R2 = 1.5kOhms, and R3 = 200Ohms, with a voltage of 1800V applied across them.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of Ohm's Law to calculate the current through each resistor. There is a question raised about whether the current through R3 should be higher due to its lower resistance, indicating some confusion about the relationship between resistance and current in parallel circuits.

Discussion Status

Some participants have provided feedback on the calculations presented, noting errors in the mathematical results and labeling. There is acknowledgment of the need for clarity regarding the behavior of resistors in parallel circuits, particularly concerning current distribution.

Contextual Notes

Participants express uncertainty about electrical circuits and the appropriateness of the topic placement. There is a mention of potential errors in calculations that may affect understanding.

MathsRetard09
Messages
22
Reaction score
0

Homework Statement



Find the current in each resistor of a parrallel circuit.

R1 = 1kOhms
R2 = 1.5kOhms
R3 = 200Ohms

The voltage is 1800V

Homework Equations



IR1 = V / R1

IR2 = V /R2

IR3 = V / R3

The Attempt at a Solution



This is what I've done:

1800V / 1000ohms = 1.8mA = R1

1800V / 1500ohms = 1.2mA = R2

1800V / 200ohms = 9mA = R3

Is R3 supposed to be higher? I don't really understand electrical circuits and furthermore i appolagise if this is in the wrong topic.
 
Physics news on Phys.org
MathsRetard09 said:

Homework Statement



Find the current in each resistor of a parrallel circuit.

R1 = 1kOhms
R2 = 1.5kOhms
R3 = 200Ohms

The voltage is 1800V

Homework Equations



IR1 = V / R1

IR2 = V /R2

IR3 = V / R3

The Attempt at a Solution



This is what I've done:

1800V / 1000ohms = 1.8mA = R1

1800V / 1500ohms = 1.2mA = R2

1800V / 200ohms = 9mA = R3

Is R3 supposed to be higher? I don't really understand electrical circuits and furthermore i appolagise if this is in the wrong topic.

Your general approach is correct, but you messed up a bit with the math and the labelling at the end.

1800V / 1000 Ohms = 1.8A, not 1.8mA. You have similar errors in the next two lines.

Also, the labels are not correct for the last 3 equations. The last 3 equations calculate I1, I2 and I3, not R1, R2 and R3.
 
Sorry i read this a while ago and forgot to thank you, yes that helped a lot. and thanks for moving it to a better location, i couldn't think cleary at the time. Thanks for your help.
 
MathsRetard09 said:
Is R3 supposed to be higher?

Yes. R3 is the lowest resistance.

Since all 3 resistors are in parallel, they all have the same voltage across them. You can therefore think of this as 3 separate circuits:
1) An 1800 volt source connected across a 1000 ohm resistor
2) An 1800 volt source connected across a 1500 ohm resistor
3) An 1800 volt source connected across a 200 ohm resistor

Now, think of these extreme cases:
1) The voltage source is not connected to anything. This is an open circuit. The resistance of the "circuit" is infinitely high and there is no current.
2) A piece of wire is connected across the terminals of the voltage source. This is a short circuit. The resistance of the circuit is very low (wire only), therefore the current is very high and either the voltage source or (more likely) the wire will burn up.


So, the answer is "yes." The R3 (the 200 ohm resistor) is the smallest load and has the highest current. This is reflected in Ohm's Law. E = I x R which, when rearranged becomes I = E/R. Dividing a number (E) by lower values (R), produces higher results (I). Conversely, dividing a number by higher values, produces lower results.
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
2K
Replies
4
Views
2K
  • · Replies 16 ·
Replies
16
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
4
Views
2K
Replies
8
Views
19K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 20 ·
Replies
20
Views
3K
  • · Replies 5 ·
Replies
5
Views
5K