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Use of Division Algorithm word problem

  1. Aug 7, 2012 #1
    1. The problem statement, all variables and given/known data

    In Florida, the fourth and fifth digits from the end of a driver's licence number give the year of birth. The last three digits for a male with birth month m and date b are represented by 40(m-1)+b. Determine the dates of birth of people who have last five digits 42218 and 53953.

    2. Relevant equations



    3. The attempt at a solution


    For license number 42218 I set up the formula:

    218=40(m-1)+b
    218=40m-30+b
    258=40m+b
    258=40(6)+18.

    June 18th 1942. (even though I consider 18 to be the fourth and fifth digits and 42 to be the first and second).




    For the second license number 53953 I set up the problem the same way and wound up with:

    993=40m+b

    I can't seem to find any m's or b's that make "Sense", i.e. m between 1 and 12 and b between 1 and 31.
     
  2. jcsd
  3. Aug 7, 2012 #2

    uart

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    Yes, from the information given, the largest number for that 3 digit code should be 11x40 + 31 = 471. So perhaps the question has a typo.
     
    Last edited: Aug 7, 2012
  4. Aug 7, 2012 #3
    That's what I was hoping! good to see i'm not missing anything.

    thank you.
     
  5. Aug 7, 2012 #4

    uart

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    Are you sure there's not some further information to that problem that we're not being told. The example says "for a male" ..., perhaps they add 500 for a female?
     
  6. Aug 7, 2012 #5
    I think you may be right. It's worded very poorly however.

    anyway, onto the next.
     
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