1. The problem statement, all variables and given/known data In Florida, the fourth and fifth digits from the end of a driver's licence number give the year of birth. The last three digits for a male with birth month m and date b are represented by 40(m-1)+b. Determine the dates of birth of people who have last five digits 42218 and 53953. 2. Relevant equations 3. The attempt at a solution For license number 42218 I set up the formula: 218=40(m-1)+b 218=40m-30+b 258=40m+b 258=40(6)+18. June 18th 1942. (even though I consider 18 to be the fourth and fifth digits and 42 to be the first and second). For the second license number 53953 I set up the problem the same way and wound up with: 993=40m+b I can't seem to find any m's or b's that make "Sense", i.e. m between 1 and 12 and b between 1 and 31.